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Luba_88 [7]
2 years ago
10

You have installed a new sound card in your system, closed the computer case, and turned on the computer. Windows boots and you

sign in but you didn't hear the familiar Windows sound that usually occurs when boot Windows. You look in Device Manager and see a device with a question mark icon. What is the most likely problem
Computers and Technology
1 answer:
ArbitrLikvidat [17]2 years ago
8 0

The most likely problem which led to the lack of sound after the installation of the new sound card is that the '<em>sound card is not recognized or incompatible</em> '

  • The sound card is an hardware which is installed into a computer in other to allow the the system produce audio signal.

  • Without a sound card installed into a computer, then such computer would not be able to perform <em>audio</em> <em>input or produce audio signals</em>.

However, when a sound card is present and, the computer fails to produce audio signal, then the most likely problem is that, the <em>sound card installed isn't recognized</em>.

Learn more :brainly.com/question/25055825

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Please help me on this coding problem :)
Vesnalui [34]

Answer:

a=4 , b=1

Explanation:

I'm not a computer science major at all but I think I can help you with this code.

Our program wants us to add 2 to a get new a value while also subtracting 1 from b value to obtain new b value. We we want to for for as long b is not 0 and a/b is nonnegative.

One round we get:

New a=0+2=2

New b=3-1=2

Let's see if we can go another round:

New a=2+2=4

New b=2-1=1

We can't go another round because b would be negative while a is positive which would make a/b negative. So our loop stops at this 2nd round.

a=4 , b=1

Other notes:

2nd choice makes no sense because a is always going to increase because of the addition on a and b was going to decrease because of the subtraction on it.

Third choice makes no sense because a/b doesn't even exist.

Fourth choice a/b is negative not nonnegative.

4 0
2 years ago
Which is true regarding pseudocode?
drek231 [11]

Answer:

It uses simple words and symbols to communicate the design of a program.

Explanation:

4 0
2 years ago
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Which item below is NOT output? A. monitor B. speakers C. printer D. mouse
Molodets [167]
D. mouse that is  your answer <span />
6 0
3 years ago
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Write a function input_poly(ptr1) that reads in two polynomials at a time with coefficient and exponent from a file cp7_in.txt.
Tanya [424]

Answer:

try this

Explanation:

#include<stdio.h>

#include<malloc.h>

typedef struct poly{ double coff;

int pow;

struct poly *link; }SL;

void create(SL **head)

{

*head=NULL;

}

//Insertion  

void ins_beg(SL ** head, double c, int pw)

{

SL *ptr;

ptr=(SL *)malloc(sizeof(SL));

ptr->coff=c;

ptr->pow=pw;

ptr->link=*head;

*head=ptr;

}

void trav(SL **head)

{

SL *ptr;

ptr=*head;

printf("\n\t Cofficient Exponent\n");

while(ptr!=NULL)

{ printf("\t\t%3.2f \t%d\n",ptr->coff, ptr->pow);

ptr=ptr->link;

}

}

//addition of polynomial............

void mult(SL *pl1, SL *pl2, SL **res)

{

SL trav1, trav2, ptr, new1,*loc;

int x,y;

trav1=*pl1;

while(trav1!=NULL)

{

trav2=*pl2;

while(trav2!=NULL)

{

x=(trav1->coff)*(trav2->coff);

y=(trav1->pow)+(trav2->pow);

//printf("\t%d\t%d\n",x,y);

if(*res==NULL)

{

new1=(SL *)malloc(sizeof(SL));

new1->coff=x;

new1->pow=y;

new1->link=NULL;

*res=new1;

}

else

{

ptr=*res;

while((y<ptr->pow)&&(ptr->link!=NULL))

{

loc=ptr;

ptr=ptr->link;

}

if(y==ptr->pow)

ptr->coff=ptr->coff+x;

else

{

if(ptr->link!=NULL)

{

new1=(SL *)malloc(sizeof(SL));

new1->coff=x;

new1->pow=y;

loc->link=new1;

new1->link=ptr;

}

else

{

new1=(SL *)malloc(sizeof(SL));

new1->coff=x;

new1->pow=y;

ptr->link=new1;

new1->link=NULL;

}

}

}

trav2=trav2->link;

}

trav1=trav1->link;

}

}

//...addition..............

void add(SL *pl1, SL *pl2)

{

SL trav1, ptr, *new1,*loc; trav1=*pl1;

while(trav1!=NULL)

{

loc=ptr=*pl2;

while((trav1->pow<ptr->pow)&&(ptr->link!=NULL))

{

loc=ptr; ptr=ptr->link;

}

if(loc==ptr)

{

new1=(SL *)malloc(sizeof(SL));

new1->coff=trav1->coff;

new1->pow=trav1->pow;

new1->link=*pl2;

*pl2=new1;

}

else

if(trav1->pow==ptr->pow)

{

ptr->coff=ptr->coff+trav1->coff;

//ptr->pow=ptr->pow+trav1->pow;

}

else

if(ptr->link!=NULL)

{

new1=(SL *)malloc(sizeof(SL));

new1->coff=trav1->coff;

new1->pow=trav1->pow;

new1->link=ptr;

loc->link=new1;

}

else

{

new1=(SL *)malloc(sizeof(SL));

new1->coff=trav1->coff;

new1->pow=trav1->pow;

new1->link=NULL;

ptr->link=new1;

}

trav1=trav1->link;

}

}

int main()

{

SL first, sec, *res;

create(&first);

ins_beg(&first,10.25,0);

ins_beg(&first,4,1);

ins_beg(&first,5,2);

ins_beg(&first,4,4);

printf("\nFirst Polinomial:\n");

trav(&first);

create(&sec);

ins_beg(&sec,11,0);

ins_beg(&sec,6,1);

ins_beg(&sec,4,2);

ins_beg(&sec,3,3);

printf("\nSecond Polinomial:\n");

trav(&sec);

create(&res);

printf("\nMultiplication of two Polinomial:\n");

mult(&first,&sec,&res);

trav(&res);

printf("\nAddition of two Polinomial:\n");

add(&first,&sec);

trav(&sec);

//trav(&first);

return 0;

}

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A 3D printer has at least how many stepper motors?
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I believe it is 200 per revolution!
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