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3 years ago

Does anyone know this answer?

Mathematics

1 answer:

choli [55]3 years ago

7 0

Answer:

The answer is Vertical

Step-by-step explanation:

Hope this helps <3

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320% expressed as a mixed number in simplest form is______________

puteri [66]

320%
= 320/100
= (320/20) / (100/20)
= 16/5
= (15+1)/ 5
= 15/5+ 1/5
= 3+ 1/5
= 3 1/5

The final answer is 3 1/5~

8 0

3 years ago

Read 2 more answers

Translate the statement into an algebraic expression. (Use "w" as a variable. Do not use "$" in your answer.

mestny [16]

Answer:

Cost = 184+50w

Step-by-step explanation:

Given statement is "Mike had $184 and he is earning $50 per week".

Here, $184 is fixed and $50 increases per week.

Let w is the variable.

ATQ,

Cost = 184+50w

Hence, the algebraic expression for the given statement is 184+50w.

4 0

3 years ago

7,676 rounded to the hundred

Tresset [83]

7,676 rounded to the nearest hundredth is: 7,700.

You are focusing on the 7676. If the 7 on the right of it has a number below five, then it would be 7600. On this hand, with it being more than 5, the correct answer is 7,700.

6 0

4 years ago

Read 2 more answers

We would like to create a confidence interval.

Vlada [557]

Answer:

c.A 90% confidence level and a sample size of 300 subjects.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level $1-\alpha$ , we have the confidence interval with a margin of error of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

In this problem

The proportions are the same for all the options, so we are going to write our margins of error as functions of $\sqrt{\pi(1-\pi)}$

a.A 99% confidence level and a sample size of 50 subjects.

$n = 50$

99% confidence interval

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The margin of error is

$M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{2.575}{\sqrt{50}}\sqrt{\pi(1-\pi)} = 0.3642\sqrt{\pi(1-\pi)}$

b.A 90% confidence level and a sample size of 50 subjects.

$n = 50$

90% confidence interval

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

The margin of error is

$M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{1.645}{\sqrt{50}}\sqrt{\pi(1-\pi)} = 0.2623\sqrt{\pi(1-\pi)}$

c.A 90% confidence level and a sample size of 300 subjects.

$n = 300$

90% confidence interval

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

The margin of error is

$M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{1.645}{\sqrt{300}}\sqrt{\pi(1-\pi)} = 0.0950\sqrt{\pi(1-\pi)}$

This produces smallest margin of error.

d.A 99% confidence level and a sample size of 300 subjects.

$n = 300$

99% confidence interval

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The margin of error is

$M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{2.575}{\sqrt{300}}\sqrt{\pi(1-\pi)} = 0.1487\sqrt{\pi(1-\pi)}$

6 0

4 years ago

Please help my sister has da struggles

Lyrx [107]

Answer: $200.

Step-by-step explanation: one tenth is just 1÷10, which is .1. Multiplying $2000 by .1 answers to $200.

7 0

3 years ago