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GaryK [48]
2 years ago
11

Each graph shows two polygons ABCD and A'B'C'D'. In each case, describe a sequence of transformations that takes `ABCD` to `A'B'

C'D'.`

Mathematics
1 answer:
morpeh [17]2 years ago
6 0
A. Reflected across the y-axis and translated one unit down

B. Rotated 90 degrees clockwise

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<span>Chris' average speed is 3.5mph: Lets take Chris' brother speed = B then Chris speed = (B+ 1) mph-------given in the question and: The average speed for covering 18 miles= chris' average speed + his brother's average speed = (B+ 1) + B since Speed = Distance covered / time taken then average speed for 18 miles can also be found by: 18 miles/3 hours = 6 miles per hour then we have; (B+ 1) + B = 6mph (B +1) = (6-B) B+B = 6-1=5 2B=5 B=5/2=2.5 mph (this is Chris' brother average speed) Hence Chris' average speed is = B+1= 2.5+1= 3.5mph</span>
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Please help find the perimeter?
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nydimaria [60]
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4 years ago
Which of the following is a true statement about perfect squares?
Lorico [155]

Answer:

A. 6 dot 6 equals 36.

Step-by-step explanation:

Hope this helps :)

7 0
3 years ago
A computer retail store has 1414 personal computers in stock. A buyer wants to purchase 33 of them. Unknown to either the retail
Lorico [155]

Answer:

a) 364 ways

b) 45.33% probability that exactly one of the computers will be defective.

c) 54.67% probability that at least one of the computers selected is defective.

Step-by-step explanation:

The computers are chosen without replacement, so we use the hypergeometric distribution to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

14 computers, so N = 14.

3 defective, so k = 3.

3 will be purchesed, so n = 3.

A) In how many different ways can the 3 computers be chosen?

3 from a set of 14. So

C_{14,3} = \frac{14!}{3!(14-3)!} = 364

364 ways

B) What is the probability that exactly one of thecomputers will be defective?

This is P(X = 1).

P(X = 1) = h(1,14,3,3) = \frac{C_{3,1}*C_{11,2}}{C_{14,3}} = 0.4533

45.33% probability that exactly one of the computers will be defective.

C) What is the probability that at least one of the computers selected is defective?

Either none is, or at least one is. The sum of the probabilities of these events is 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1). Then

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = 0) = h(0,14,3,3) = \frac{C_{3,0}*C_{11,3}}{C_{14,3}} = 0.4533

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.4533 = 0.5467

54.67% probability that at least one of the computers selected is defective.

5 0
3 years ago
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