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3 years ago

How would you graph 10<=20

Mathematics

2 answers:

irinina [24]3 years ago

8 0

Answer:

with a line

Step-by-step explanation:

so you get a use a graph calculator and you put in that and it shows the answer.

Klio2033 [76]3 years ago

3 0

Answer:With a life

Explanation: yeah that’s the answer

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indicate the equation of the given line in standard form. the line that contains the point q(1,-2) and is parallel to rhe line w

iren2701 [21]

Since the lines are parallel they have the same slope 2/3. use point slope form to get,

y+2=2/3(x-1)

y+2=2/3x-2/3

y=2/3x-8/3

3y=2x-8

2x-3y=8

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3 years ago

What does impeach mean?

ziro4ka [17]

Answer:

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2 years ago

How to find imaginary zeros anf real zeros of F(x)=-4x^5-8x^3+12x

Fofino [41]

Answer:

$x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}$

Step-by-step explanation:

We are given the function:

$f(x)=-4x^5-8x^3+12x$

And we want to finds its zeros.

Therefore:

$0=-4x^5-8x^3+12x$

Firstly, we can divide everything by -4:

$0=x^5+2x^3-3x$

Factor out an x:

$0=x(x^4+2x^2-3)$

This is in quadratic form. For simplicity, we can let:

$u=x^2$

Then by substitution:

$0=x(u^2+2u-3)$

Factor:

$0=x(u+3)(u-1)$

Substitute back:

$0=x(x^2+3)(x^2-1)$

By the Zero Product Property:

$x=0\text{ and } x^2+3=0\text{ and } x^2-1=0$

Solving for each case:

$x=0\text{ and } x=\pm\sqrt{-3}\text{ and } x=\pm\sqrt{1}$

Therefore, our real and complex zeros are:

$x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}$

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3 years ago

Solve the inequality.<br><br> 3≤7+g

Anastaziya [24]

Answer:

g-4

Step-by-step explanation:

first subtract 7 from both sides

then you will get -4 $\leq$ g

which is the same as g $\geq$ -4

you just have to switch them

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3 years ago

Read 2 more answers

Help ASAP

CaHeK987 [17]

About 3.7 inches. Look at the 12 on the x axis because that is one year and see where it hits the line

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3 years ago