I’m not for sure of the answer but i do know that the two subtractions in the middle would turn into a + and i think you add the -5/8 + 3/10
I’m assuming the question is to find the number of calls made? If so here’s how to solve it.
18 + 0.5x = 50.50
.05x = 32.50
x = 650
650 calls made.
Answer:
This is because if you subtract 16 by 4, and 16 minus 3, you get 13 and 12 as the quotients. Now, you want to add these 2 numbers together, which gives you 25.
Hi,
BC²=CA²-BA²=13-9=4=2² (Pythagore)
CB/ED=AB/AD (Thalès)
2/2.5=3/AD==>AD=3*2.5/2=7.5/2
DB=DA-AB=7.5/2-3=0.75
I don't know how you call this 2 theorems (sorry)
Answer:
P(t) = 2093e^(42t).
Step-by-step explanation:
The population of this town can be modeled by the following differential equation
dP/dt = Pr
where r is the growth rate in people a year.
We can solve this differential equation by the separation of variables method.
dP/P = rdt
Integrating both sides, we have:
ln P = rt + P0
where P0 is the initial population
To isolate P, we do this:
e^(ln P) = e^(rt + P0)
P(t) = P0e^(rt).
We have that the population increases by 42 people a year, so r = 42. We also have that the population at time t = 0 is 2093 people, so P0 = 2093.
So the formula for the population, P, of the town as a function of year t is P(t) = 2093e^(42t).