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3 years ago

Which information proves that ||?

Mathematics

2 answers:

marin [14]3 years ago

6 0

Answer:

the answer it C.

Step-by-step explanation:

its just right

denis-greek [22]3 years ago

6 0

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

The given lines are parallel only when :

∠4 ≅ ∠6

because they form pair of alternate interior angles.

So, correct choice is C

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Nicole is making tuna salad for her office colleagues. It takes 2/5 of a pound of canned tuna to make 5 portions of salad. She u

jeka94

Answer:

She makes 30 portions.

Step-by-step explanation:

To find, you would multiply the amount of tuna you need by the number of onions nicole used.

6/5x2 = 12/5

12/5 ÷ 2/5 = 6

6x5 = 30

She makes 30 portions.

3 0

2 years ago

Only 4 and 5 help help

stich3 [128]

Pythagorean theorem is a^2 + b^2 =c^2 4)8.9
5)6.7

4 0

3 years ago

Read 2 more answers

I know I already asked this, but I forgot to mention this. m over + m when m equals -6

snow_lady [41]

Hello there!

m/2

-6/2

-6/2 = -3

Your answer is -3

Hope I helped!

Let me know if you need anything else!

~ Zoe

6 0

4 years ago

Read 2 more answers

1500 customers hold a VISA card; 500 hold an American Express card; and, 75 hold a VISA and an American Express. What is the pro

alex41 [277]

Answer:

There is 15% probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

$P(VISA \:| \:AE) = 15\%\\$

Step-by-step explanation:

Number of customers having a Visa card = 1,500

Number of customers having an American Express card = 500

Number of customers having Visa and American Express card = 75

Total number of customers = 1,500 + 500 = 2,000

We are asked to find the probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

This problem is related to conditional probability which is given by

$P(A \:| \:B) = \frac{P(A \:and \:B)}{P(B)}$

For the given problem it becomes

$P(VISA \:| \:AE) = \frac{P(VISA \:and \:AE)}{P(AE)}$

The probability P(VISA and AE) is given by

P(VISA and AE) = 75/2000

P(VISA and AE) = 0.0375

The probability P(AE) is given by

P(AE) = 500/2000

P(AE) = 0.25

Finally,

$P(VISA \:| \:AE) = \frac{P(VISA \:and \:AE)}{P(AE)}\\\\P(VISA \:| \:AE) = \frac{0.0375}{0.25}\\\\P(VISA \:| \:AE) = 0.15\\\\P(VISA \:| \:AE) = 15\%\\$

Therefore, there is 15% probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

8 0

3 years ago

What's the vertex for y=2x^2-12x+19

Sati [7]

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3 years ago