Please help me. I will mark as brainliest give correct answer.

Write the word form and the expanded form for each 1.7 & 5.62

Mrac [35]

1.7 = One and seven tenths
5.62 = Five and sixty-two hundredths

6 0

3 years ago

Read 2 more answers

A carrot has a volume of 200cubic centimeters and a mass of 80grams. Calculate its density.

valentinak56 [21]

Density=m/V
m=80 gr
V=200cm^3
Density=80gr/200cm^3
Density=0.4 gr per cubic centimeter

4 0

2 years ago

What is the area of this trapezoid?

Ivanshal [37]

Answer: 357 cm²

Step-by-step explanation: In this problem, were asked to find the area of the trapezoid shown. Remember that a trapezoid is a quadrilateral with one pair of parallel sides. The formula for the area of a trapezoid is shown below

The b's are the bases or the parallel sides and the h represents the height.

So in the trapezoid shown, the bases are 15 cm and 27 cm and the height is 17 cm.

Plugging this information into the formula, we have .

Next, the order of operations tells us that we must simplify inside the parentheses first. 15 cm + 27 cm is 42 cm and we have

1/2 × 42 cm is 21 cm and we have (21 cm)(17 cm) which is 357 cm².

So the area of the trapezoid shown is 357 cm².

5 0

3 years ago

Please get me the answer

Anna71 [15]

Answer:

i belive its A $15

Step-by-step explanation:

if $3 is 20% and we are trying to find the full 100% then you miltiply 3 by 5 since 20 times 5 equals 100 and when you multiply 3 by 5 you get 15 dollars which is 100 percent of the iteam meaning the regular price.

3 0

2 years ago

A simple random sample of 110 analog circuits is obtained at random from an ongoing production process in which 20% of all circu

telo118 [61]

Answer:

64.56% probability that between 17 and 25 circuits in the sample are defective.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .