1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
andriy [413]
3 years ago
8

What is the answer to this question?

Mathematics
2 answers:
ra1l [238]3 years ago
5 0

Answer:

a

Step-by-step explanation:

just multiply

please do the brainiest thing

Naddika [18.5K]3 years ago
5 0

Answer: area = 75.04 in2

Step-by-step explanation:

Area = l*b = 11.2*6.7

= 75.04 in2

You might be interested in
Find the slope of the line.
pickupchik [31]
There are several ways to do this.
I'll show you two methods.

1) Pick two points on the line and use the slope formula.
Look for two points that are easy to read. It is best if the points are on grid line intersections. For example, you can see points (-4, -1) and (0, -2) are easy to read.
Now we use the slope formula.

slope = m = (y2 - y1)/(x2 - x1)

Call one point (x1, y1), and call the other point (x2, y2).
Plug in the x1, x2, y1, y2 values in the formula and simplify the fraction.

Let's call point (-4, -1) point (x1, y1).
Then x1 = -4, and y1 = -1.
Let's call point (0, -2) point (x2, y2).
Then x2 = 0, and y2 = -2.

Plug in values into the formula:

m = (y2 - y1)/(x2 - x1) = (-2 - (-1))/(0 - (-4)) = (-2 + 1)/(0 + 4) = -1/4

The slope is -1/4

2) Pick two points on the graph and use rise over run.
The slope is equal to the rise divided by the run.
Run is how much you go up or down.
Rise is how much you go right or left.

Pick two easy to read points.
We can use the same points we used above, (-4, -1) and (-0, -2).
Start at point (0, -2).
How far up or down do you need to go to get to point (-4, -1)?
Answer: 1 unit up, or +1.
The rise is +1.
Now that we went up 1, how far do you go left or right top go to point (-4, -1)?
Answer: 4 units to the left. Going left is negative, so the run is -4.
Slope = rise/run = +1/-4 = -1/4

As you can see we got the same slope using both methods.
6 0
4 years ago
HELP! I will mark you the brainiest!
Ymorist [56]
#5: cost: y
Number of beads: x
y=0.48*x
So for 4 beads: 1.92
for 5 beads: 2.4

#6: the x th term in the sequence is y
y=17-2x
The 10th term is -3
6 0
4 years ago
Read 2 more answers
Convert from radians to degrees. Show all work. You can type pi for the symbol <br> 7/12 pi
mariarad [96]

Answer:

The answer is \frac{7\pi }{12}^{c}=105^{0}

Step-by-step explanation:

The expression is

\frac{7\pi }{12}^{c}\\= \frac{7\pi }{12}*\frac{180}{\pi }^{0} \,;[1^{c}=\frac{180}{\pi}^{0}]\\=7*15\\=105^{0}

Hope you have understood this....

pls mark my answer as the brainliest

8 0
3 years ago
PLEASE HELP ASAP!! WILL MARK BRAINLIEST
KATRIN_1 [288]
The slope is mx+b so find two points in the graph and use y-rise/x-run 
8 0
4 years ago
Read 2 more answers
Find the area of a triangle with a base length of 3 units and a height of 4 units.
eduard
A = 1/2bh
= 1/2(3)(4)
=1/2(12)
=6
The area of the triangle is: B) 6 units. 

Hope this helps!
4 0
3 years ago
Other questions:
  • Isandro and Yvette each have a calculator. Yvette starts at 100 and subtracts 7 each time. Isandro on the other hand, starts at
    6·1 answer
  • Can you answer this? <br> factorise 6p + 24q
    6·1 answer
  • Gina is a salesperson at a furniture store. She earns 2,500 per month plus a commission of 12% on an all her sales. In order to
    15·1 answer
  • I NEED THIS FASTTT
    6·1 answer
  • WILL MARK BRAINLIEST!!!! BRAINLIEST!<br> Write 206 in base 7
    6·2 answers
  • Plz help I’m getting timed
    5·1 answer
  • which of the points (s,t) is inside the shaded region of the set of inequalities qualities shown below?
    12·1 answer
  • There are 100 centimeters (cm) in every meter (m).
    15·1 answer
  • Solve simultaniously<br> 2x-y=3<br> 3x+2y=8
    15·2 answers
  • Help me to solve this question
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!