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nignag [31]
2 years ago
11

NO LINKS! PLS HELP 40PTS!! PLS DO IT RIGHT! IM DOUBLE CHECKING!!! PLS HURRY​

Mathematics
1 answer:
Zarrin [17]2 years ago
5 0

You have to multiply every number!!

Example: 8 x 6 x 3 x 3 x 4

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The sale is being held from 11 a.m to 7 p.m on sunday, and from 9 a.m to 7 p.m on monday. How many hours will the sale last?​
PSYCHO15rus [73]
8+10=18as your final answer
3 0
3 years ago
Read 2 more answers
C(x)=4x-2 and d(x)=x^(2)+5, what is (c*d)(x)
lawyer [7]

Answer:4x^3-2x^2+20x-10

Step-by-step explanation:

5 0
3 years ago
1 question 60 points need help now
kkurt [141]

Answer:

The answer to your question is  x = 0 and x = 1

Step-by-step explanation:

Equation

                       \frac{x}{x - 2} + \frac{x - 1}{x + 1} = -1

1)

                      \frac{x(x + 1) + (x - 2)(x - 1)}{(x - 2)(x + 1)} = - 1

Expand

2)                  x² + x + x² - x - 2x + 2 = -1(x - 2)(x + 1)

Simplify

3)                  2x² -2x + 2 = -1(x² + x - 2x - 2)

4)                  2x² - 2x + 2 = -x² + x + 2

Equal to zero

5)                  2x² - 2x + 2 + x² - x - 2 = 0

6)                  3x² - 3x = 0

Factor

7)                  3x(x - 1) = 0

8)                  3x₁ = 0                   x₂ - 1 = 0

9)                    x₁ = 0/3                x₂ = 1

10)                  x₁ = 0                    x₂ = 1

4 0
3 years ago
A ball, with an initial position of x = 25.89 meters, undergoes a displacement of 32.2 meters. What is it’s final position?
Snowcat [4.5K]

Answer:

The answer is 58.09

Step-by-step explanation:

To get the final position, you add the displacement to the initial position.

Final position = 25.89 + 32.2

Final position = 58.09metres

4 0
3 years ago
In a local basketball league championship total 198 games were played, where each team played exactly three games with all the o
kifflom [539]

Answer:

  12

Step-by-step explanation:

When n teams play each other once, the total number of games is n(n-1)/2. Since each team played every other one 3 times, the relationship between number of teams (n) and number of games is ...

  3(n(n-1)/2) = 198

  n(n-1) = 132 = 12·11 . . . . . . multiply by 2/3 and factor

  n = 12 . . . . . . n = -11 is also an extraneous solution to this quadratic equation

12 teams participated in this championship.

6 0
3 years ago
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