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Ilya [14]
3 years ago
8

What is (18-26)^3can oneone help me get 5 more brainlyistand 400 points

Mathematics
1 answer:
Phoenix [80]3 years ago
3 0

Answer:  -512

Step-by-step explanation:

(18-26) = -8

(-8)^3 = (-8)*(-8)*(-8) = -512

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Consider the following functions.G(x) = 4x2; f(x) = 8x(a)
noname [10]

Answer:

(a) B. G(x) is an antiderivative of f(x) because G'(x) = f(x) for all x.

(b) Every function of the form 4x^2+C is an antiderivative of 8x

Step-by-step explanation:

A function <em>F </em>is an antiderivative of the function <em>f</em> if

F'(x)=f(x)

for all x in the domain of <em>f.</em>

(a) If f(x) = 8x, then G(x)=4x^2 is an antiderivative of <em>f </em>because

G'(x)=8x=f(x)

Therefore, G(x) is an antiderivative of f(x) because G'(x) = f(x) for all x.

Let F be an antiderivative of f. Then, for each constant C, the function F(x) + C is also an antiderivative of <em>f</em>.

(b) Because

\frac{d}{dx}(4x^2)=8x

then G(x)=4x^2 is an antiderivative of f(x) = 8x. Therefore, every antiderivative of 8x is of the form 4x^2+C for some constant C, and every function of the form 4x^2+C is an antiderivative of 8x.

8 0
3 years ago
Need help figuring this one out
Dennis_Churaev [7]

Answer:

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Step-by-step explanation:

First, I found what 540 multiplied by 0.0000000028 was. Next, I took 66921428571428.6 and divided it by the product I got on top.

7 0
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The weights of the fish in a certain lake are normally distributed with a mean of 18 lb and a standard deviation of 12. if 16 fi
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<span>The weights of the fish in a certain lake are normally distributed with a mean of 18 lb and a standard deviation of 12. </span>
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I WILL GIVE BRAINLIEST PLEASE ANSWER FAST
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This link does not go to anywhere
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Need heeeelp please ​
Juliette [100K]

Answer:

7.61577310586

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Pythagoras Theorem 7 squared + 3 squared= 49+9=58

\sqrt{58}

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