Answer:
6°F
58°F
Step-by-step explanation:
From the data Given :
Temperature rise in Buffalo by noon time = 14°F
The initial temperature at Buffalo = - 8°F
Rise in temperature = 14°F
Therefore, temperature at noon = (-8 + 14)°F = 6°F
B.)
Temperature at 6am in St. Louis = 32°F
Temperature at 6am in Juneau = - 26°F
Temperature difference :
(32 - (-26))°F
32 + 26
= 58°F
Temperature in St. Louis is 58°F higher
Answer: 2/1
Step-by-step explanation:
Answer:
d. quadrilateral
Step-by-step explanation:
(x + 8)(x - 6)
to factorise consider the factors of - 48 which sum to + 2
These are + 8 and - 6 thus
x² + 2x - 48 = (x + 8)(x - 6)
