Cirrus clouds form at a height of more than 6000 meters above the earth. This means the inequality should represent the height more than 6000. The correct inequality for this case will be:
![h\ \textgreater \ 6000](https://tex.z-dn.net/?f=h%5C%20%5Ctextgreater%20%5C%206000)
This inequality shows that h which is height where Cirrus clouds are formed is greater than 6000m.
We have
![\left(\dfrac{2}{3}\right)^x=\dfrac{2^x}{3^x}](https://tex.z-dn.net/?f=%5Cleft%28%5Cdfrac%7B2%7D%7B3%7D%5Cright%29%5Ex%3D%5Cdfrac%7B2%5Ex%7D%7B3%5Ex%7D)
And we want
![\dfrac{2^x}{3^x}=\dfrac{16}{81}=\dfrac{2^4}{3^4}](https://tex.z-dn.net/?f=%5Cdfrac%7B2%5Ex%7D%7B3%5Ex%7D%3D%5Cdfrac%7B16%7D%7B81%7D%3D%5Cdfrac%7B2%5E4%7D%7B3%5E4%7D)
Another way to read it is
![\dfrac{16}{81}=\left(\dfrac{2}{3}\right)^4=\left(\dfrac{2}{3}\right)^x](https://tex.z-dn.net/?f=%5Cdfrac%7B16%7D%7B81%7D%3D%5Cleft%28%5Cdfrac%7B2%7D%7B3%7D%5Cright%29%5E4%3D%5Cleft%28%5Cdfrac%7B2%7D%7B3%7D%5Cright%29%5Ex)
It should be clear that the solution is ![x=4](https://tex.z-dn.net/?f=x%3D4)
Answer:
It has to be less than 20 kids per team.
Step-by-step explanation:
Because 1107/56 is 19.767857142.
First you need to distribute the 1/2 by the numbers in the parentheses
1/2•4x and 1/2•10 which equals
2x+5=10
next, you will need to get the 2x by itself so you would do
2x+5=10
-5=-5
2x=5
finally, you divide the 2 by the 5 so you can get the x by itself
2x divided by 5
the answer is: x=2.5
Answer:
(a) 2.22
(b) 1.3986
(c) 1.183
Step-by-step explanation:
Let <em>X</em> denote the number of women who consider themselves fans of professional baseball.
The proportion of women who consider themselves fans of professional baseball is, <em>p</em> = 0.37.
A random sample of <em>n</em> = 6 women are selected and each was asked if she considers herself a fan of professional baseball.
Each woman's reply is independent of the others.
The random variable <em>X</em> thus follows a binomial distribution with parameters <em>n</em> = 6 and <em>p</em> = 0.37.
(a)
Compute the mean of the binomial distribution as follows:
![\text{Mean}=np=6\times 0.37=2.22](https://tex.z-dn.net/?f=%5Ctext%7BMean%7D%3Dnp%3D6%5Ctimes%200.37%3D2.22)
(b)
Compute the variance of the binomial distribution as follows:
![\text{Variance}=np(1-p)=6\times 0.37\times (1-0.37)=1.3986](https://tex.z-dn.net/?f=%5Ctext%7BVariance%7D%3Dnp%281-p%29%3D6%5Ctimes%200.37%5Ctimes%20%281-0.37%29%3D1.3986)
(c)
Compute the standard deviation of the binomial distribution as follows:
![\text{Standard Deviation}=\sqrt{np(1-p)}=\sqrt{6\times 0.37\times (1-0.37)}=1.183](https://tex.z-dn.net/?f=%5Ctext%7BStandard%20Deviation%7D%3D%5Csqrt%7Bnp%281-p%29%7D%3D%5Csqrt%7B6%5Ctimes%200.37%5Ctimes%20%281-0.37%29%7D%3D1.183)