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Mandarinka [93]
3 years ago
14

Please help me.......​

Mathematics
1 answer:
Vesna [10]3 years ago
8 0

Answer:

<h2>1</h2>

Step-by-step explanation:

I hope this helps

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Solve for q(x) and r(x). (4x^3-3x^2+5x-7)/(x-2) = q(x)+ r(x)/(x-2)
4vir4ik [10]
By synthetic division,

q(x) = 4x^2 +5x +15

r(x) = 23

7 0
3 years ago
$4.99 for 6 cans or $7.99 for 10 can
4vir4ik [10]
I would put $7.99 for 10 can
3 0
4 years ago
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The equivalent fraction to 4/4
Sonbull [250]

Answer:

1/1

Step-by-step explanation:

if u divide 4 divided by 4 then its 1

8 0
3 years ago
What is equation is equivalent to 6(3p-2)=20?
Simora [160]

Answer:

p=\frac{16}{9}

Step-by-step explanation:

6(3p-2)=20

Distribute the brackets.

6(3p)+6(-2)=20

18p-12=20

Add 12 on both sides.

18p-12+12=20+12

18p=20+12

18p=32

Divide 18 on both sides.

\frac{18p}{18}=\frac{32}{18}

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4 0
3 years ago
Read 2 more answers
Erica is participating in a road race. The first part of the race is on a 5.2-mile-long straight road-oriented at an angle of 25
kap26 [50]

Answer:

6.31 mi

Step-by-step explanation:

The diagram below explains the solution better.

From the diagram,

C = starting point of the race.

A = end of the first part of the race.

B = end of the race.

Using Cosine rule, we can find the straight-line distance between the starting point and the end of the race.

Cosine rule states that:

a^2 = b^2 + c^2 - 2bc[cos(A)]

where A = angle A = <A

Given that

b = 5.2 miles

c = 2.0 miles

<A = 115° (from the diagram)

Hence,

a^2 = 5.2^2 + 2.0^2 - 2*5.2*2.0[cos(115)]\\\\a^2 = 27.04 + 4 - 20.8[cos(115)]\\\\a^2 = 31.04 + 8.79\\\\a^2 = 39.83\\\\a = \sqrt{39.83}\\ \\a = 6.31 mi

The straight-line distance between the starting point and the end of the race is 6.31 mi

4 0
3 years ago
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