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djverab [1.8K]
3 years ago
10

Emily has 12 fruits in her bowl. She has 3 apples, 5 bananas, 1 pear and 3 oranges. A fruit is selected at random. What is the p

robability that the fruit is an orange or a pear? A. 56 B. 23 C. 12 D. 13
Mathematics
1 answer:
blsea [12.9K]3 years ago
5 0

Answer: The probability that the fruit is an orange or a pear is \dfrac{1}{3} .

Step-by-step explanation:

Given : Emily has 12 fruits in her bowl.

She has 3 apples, 5 bananas, 1 pear and 3 oranges.

A fruit is selected at random.

P(orange)  = \dfrac{\text{Number of oranges}}{\text{Total fruits}}

=\dfrac{3}{12}

P(pear)= \dfrac{\text{Number of pears}}{\text{Total fruits}}

=\dfrac{1}{12}

Since both events of selecting orange and pear are mutually exclusive , so

The probability that the fruit is an orange or a pear = P(orange) + P(pear)

=\dfrac{3}{12}+\dfrac{1}{12}=\dfrac{4}{12}=\dfrac{1}{3}

Therefore , the probability that the fruit is an orange or a pear is \dfrac{1}{3} .

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