7x-3x=7+5
4x=12
X=3
This is the answer
The answer is 7/69.
There are 8 black-haired children among 24 children. The probability of <span>randomly selecting black haired children for the first time is:
P1 = 8/24 = 1/3
Now, there are 7 black-haired children left among 23 children. The probability of </span>randomly selecting black haired children for the second time is:
P2 = 7/23
Since we want both of these events to occur together, we will multiply their probabilities:
P = P1 * P2 = 1/3 * 7/23 = 7/69
Answer:
Adults=8
Childrens=2
Seniors=2
Step-by-step explanation:
Children $4
Adults $6
Seniors $5
There are an equal number of seniors and children.
The entire group spent a total of $66.
If 11 adults attended, the total amount will be $66 and the number of senior and childrens will be the same, 0. But this is not possible because the statement says that childrens and seniors are part of the group.
If we add the charges of childrens and seniors is equal to $9.
Assuming that the group has 2 childrens and 2 seniors the add is equal to:
Now we substract the result from the total amount:

48 is multiple of 6, this means we have in the group 8 adults, 2 childrens and 2 seniors.