Complete Question
Determine whether the normal sampling distribution can be used. The claim is p < 0.015 and the sample size is n=150
Answer:
Normal sampling distribution can not be used
Step-by-step explanation:
From the question we are told that
The null hypothesis is 
The alternative hypothesis is 
The sample size is n= 150
Generally in order to use normal sampling distribution
The value 
So
Given that 
normal sampling distribution can not be used
Answer:
false
Step-by-step explanation:
32 = 6(1) - 4
According to PEMDAS (parentheses/exponents | multiplication/division | additions/subtraction), we should multiply first.
32 = 6 - 4
Now let's subtract.
32 = 2
This statement is incorrect; therefore it is not true.
The decimal adds a zero every time the powers of ten increase for example if u do 1 x
=100 if u do 1x
=1,000
-3/8 = -0.375
-5/8 = -0.625
-1/8 = -0.125
1/4 = 0.25
<span>0.5 = 0.5
</span>
Therefore 1/4 & 0.5 & -1/8 > -3/8
Answer:
h(x) = 2^(x) - 1.
Step-by-step explanation:
Let's look at each equation:
f(x) = -3x +7, Well as x increases, since it's multiplication, there are "going to be more" -3's, so it's going to be decreasing.
g(x) = -4(2^x). While 2^x is increasing, because "there are going to be more 2's multiplied by each other" as x increases, it's being multiplied by a negative number, so it's actually going to be decrasing
h(x) = 2^(x) - 1. Here's it's going to be increases as x goes towards infinity because "there are going to be more 2's multiplied by each other", and there isn't any negative sign, while there is a negative 1, it's constant, so the overall value will be increasing
