3 years ago

Sas, sss, aas, or not enough information

Mathematics

1 answer:

lesya [120]3 years ago

3 0

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

The given triangles are congruent by :

ASA criterion

because they have Two Angles and a side between them equal to the corresponding Angles and side of the another triangle.

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Which of the following could not be points on the unit circle?

NemiM [27]

A. √(0.8^2) + (0.6^2) = √1 = 1 => OK

<span>b.(-2/3,√ 5/3) = √(-2/3)^2 + 5/9) = √(4/9 +5/9) = √1 = 1 => OK

c.(√ 3/2, 1/3) = √(3/4 + 1/9) < 1 => it is inside the unit circle

d.(1,1) = √(1 + 1) = √2 > 1 => NO. This point is beyond the limits of the unit circle.</span>

4 0

3 years ago

Read 2 more answers

Question 1 (3 points) What value of p makes this equation true? 3p - 8 = -23 . O p = -6 Op = -5 Op = 5 p = 6

olchik [2.2K]

The value of p that makes the given equation true is equal to: B. p = -5

<u>Given the following equation:</u>

$3p - 8 = -23$

To find a value of p that makes the given equation true:

In this exercise, you're required to determine a value of p that satisfies the given equation true such that when substituted into the equation, it has a true result or outcome.

Rearranging the equation by collecting like terms, we have:

$3p - 8 = -23\\\\3p=-23+8\\\\3p=-15\\\\p=\frac{-15}{3}$