It should be 21 I believe at least if not sorry
Answer:
20.058
Step-by-step explanation:
401.16 x 0 05
= 20 058
Answer:
-4
Step-by-step explanation:
4,000×((1+0.05)^(15)−1)÷0.05
=86,314.25
86,314.25−86,314.25×0.15
=73,367.11
Answer: Our required probability is 0.07 i.e. 0.1.
Step-by-step explanation:
Let A be the event that "the person is infected".
Let B be the event that "the person tests positive".
Probability of person is positive if the person has the virus = 85%
Probability of person is positive if the person does not have the virus = 5%
P(B|A) = 0.85
So, P(A) = ![\dfrac{1}{200}=0.005](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B200%7D%3D0.005)
P(B) is given by
![\dfrac{1}{200}\times 0.85+\dfrac{199}{200}\times 0.05\\\\=0.00425+0.04975\\\\=0.054](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B200%7D%5Ctimes%200.85%2B%5Cdfrac%7B199%7D%7B200%7D%5Ctimes%200.05%5C%5C%5C%5C%3D0.00425%2B0.04975%5C%5C%5C%5C%3D0.054)
So, We need to find P(A|B) which is given by
![P(A|B)=P(B|A)\times \dfrac{P(A)}{P(B)}\\\\P(A|B)=0.85\times \dfrac{0.005}{0.054}\\\\P(A|B)=0.0787](https://tex.z-dn.net/?f=P%28A%7CB%29%3DP%28B%7CA%29%5Ctimes%20%5Cdfrac%7BP%28A%29%7D%7BP%28B%29%7D%5C%5C%5C%5CP%28A%7CB%29%3D0.85%5Ctimes%20%5Cdfrac%7B0.005%7D%7B0.054%7D%5C%5C%5C%5CP%28A%7CB%29%3D0.0787)
Hence, our required probability is 0.07 i.e. 0.1.