Well, is namely their difference, so, let's first convert the mixed fractions to "improper", and subtract.
Step-by-step explanation:
7.2 / (-8.1) / (-3.7) = Positive
A = (-7.2) / (-8.1) / (-3.7) = Negative
B = (-7.2) / (8.1) / (3.7) = Negative
Hence the answer is C, none of the above.
Hi! Your answer is q = -9
Please see an explanation for a better and clear understanding to your problem.
Any questions about my answer and explanation can be asked through comments! :)
Step-by-step explanation:
Since we want to solve for q-term. That means we are going to isolate q-term.

We can add 4 and 9 together.

Because we want to know the value of q. That means we have to isolate q-term by subtracting both sides by 13.

We are reaching to the final step where we divide the whole equation by 3.

Finally, the solution for this equation is q = -9. But what if you are not certain or sure about the answer? Let's check it out!
To check the answer, simply substitute q = -9 in the equation.

Notice that the equation is true for q = -9. Hence, we can conclude that the solution for this equation is q = -9.
Hope this helps!
Answer:
Test scores of 10.2 or lower are significantly low.
Test scores of 31 or higher are significantly high
Step-by-step explanation:
Z-score:
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Significantly low:
Z-scores of -2 or lower
So scores of X when Z = -2 or lower




Test scores of 10.2 or lower are significantly low.
Significantly high:
Z-scores of 2 or higher
So scores of X when Z = 2 or higher




Test scores of 31 or higher are significantly high
Answer is D. Add the equations in order to solve for the first variable. Plug this value into the other equations in order to solve for th remaining varables