Ok! So, given a quadratic function<span>, </span>y<span> = ax</span>2<span> + bx + c, when "a" is positive, the </span>parabola <span>opens upward and the vertex is the minimum value. On the other hand, if "a" is negative, the graph opens downward and the vertex is the maximum value. Now, let's refer back to our original graph, </span>y<span> = </span><span>x2</span><span>, where "a" is 1.
Hope this helps.</span>
Answer:
(x, y) = (-3, -6)
Step-by-step explanation:
The second equation can be used to write an expression for y:
... -5x -21 = y . . . . . . . add y-21 to both sides
This expression can be substituted for y in the first equation:
... 6 = -4x +(-5x -21)
... 27 = -9x . . . . . add 21, collect terms
... -3 = x . . . . . . . divide by -9
Using this value of x in the expression for y, we find ...
... -5(-3) -21 = y = -6
The solution is x = -3, y = -6.
Answer:
e
Step-by-step explanation:
e
Answer:
<h2 /><h2>The interquartile range (IQR) is the difference between the upper (Q3) and lower (Q1) quartiles, and describes the middle 50% of values when ordered from lowest to highest. The IQR is often seen as a better measure of spread than the range as it is not affected by outliers. Interquartile Range. 25% of values.</h2>
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<h2>here your answer </h2>
A function assigns the values. The graph can be plotted as shown below.
<h3>What is a Function?</h3>
A function assigns the value of each element of one set to the other specific element of another set.
Given the function, g(x) = -3(1/2)ˣ, therefore, the value of g(x) can be written as,
g(x) = -3(1/2)ˣ
g(-2) = -3(1/2)² = -0.75
g(-1) = -3(1/2)¹ = -1.5
g(0) = -3(1/2)⁰ = -3
g(1) = -3(1/2)¹ = -1.5
Hence, the graph can be plotted as shown below.
Learn more about Function:
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