A=adult pay
c=child pay
3a+4c=83
2a+3c=59
subtract
a+c=24
2a+2c=48
2a+3c-2a-2c=59-48
c=11
a=24-11=13
price of adult ticket=13$
price of child's ticket=$11
Answer:
1680
Step-by-step explanation:
280 x 6 = 1680
Answer:
The slopes are
Therefore, the equations are equations of <u> Perpendicular Lines .</u>
Step-by-step explanation:
Given:
......................Equation ( 1 )
..............Equation ( 2 )
To Find:
Slope of equation 1 = ?
Slope of equation 2 = ?
Solution:
On comparing with slope point form
Where,
m = Slope
c = y-intercept
We get
Step 1.
Slope of equation 1 = m1 = 
Step 2.
Slope of equation 1 = m2 = 
Step 3.
Product of Slopes = m1 × m2 = 
Product of Slopes = m1 × m2 = -1
Which is the condition for Perpendicular Lines
The slopes are
Therefore, the equations are equations of <u> Perpendicular Lines . </u>
15. n - 6 = 21......add 6 to both sides
n = 21 + 6
n = 27
16. p + 1 3/4 = 4 5/8...turn mixed numbers to improper fractions
p + 7/4 = 37/8....there is 2 ways to continue from here...I will show u both
(1) p + 7/4 = 37/8....multiply everything by common denominator of 8, this gets rid of the fractions.
8p + 14 = 37 (result of multiplying by 8)
8p = 37 - 14
8p = 23
p = 23/8
(2) p + 7/4 = 37/8...subtract 7/4 from both sides
p = 37/8 - 7/4...common denominator is 8
p = 37/8 - 14/8
p = 23/8
either way u use, u will arrive at the same answer
Well I know that c. goes with I. just because I saw so many x^3 graphs.
For a. the parent function is x^2, so 0.5x^2 should look about the same as x^2, so the answer is VI.
