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2 years ago

What is the LCM for 12 and 14 step by step Ladder method or factors method

2 answers:

6 0

erma4kov [3.2K]2 years ago

3 0

12, 24, 36 , 48, 60, 72, 84

14, 28, 42, 56, 70, 84
The LCM is 84

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What is the absolute value equation for this graph?

Delvig [45]

Answer:

y = |x-3| -1

Step-by-step explanation:

The parent function has been shifted right 3 units and down 1 unit. That is f(x)=|x| has been moved to ...

y = f(x -3) -1

y = |x -3| -1 . . . . matches the last choice

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2 years ago

Subtract: 114.8 – 8.34 A) 106.46 B) 106.54 C) 116.54 D) 116.56

Colt1911 [192]

The answer is 106.46. A

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3 years ago

Read 2 more answers

Solve for p. <br><br> i = prt<br><br> p = i-rt<br> p = i/(rt)<br> p = (rt)/i

Debora [2.8K]

Answer:

Step-by-step explanation:

$i=prt\to prt=i\qquad\text{divide both sides by}\ rt\neq0\\\\\dfrac{prt}{rt}=\dfrac{i}{rt}\\\\p=\dfrac{i}{rt}$

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3 years ago

Daily low temperatures in Columbus, OH in January 2014 were approximately normally distributed with a mean of 15.45 and a standa

Alona [7]

Answer: 12.10

Step-by-step explanation:

Given : Mean : $\mu = 15.45$

Standard deviation : $\sigma = 13.70$

The formula to calculate the z-score :-

$z=\dfrac{x-\mu}{\sigma}$

For x= 5 degrees

$z=\dfrac{5-15.45}{13.70}=-0.7627737226\approx-0.76$

For x= 10 degrees

$z=\dfrac{10-15.45}{13.70}=-0.397810218\approx-0.40$

The P-value : $P(-0.76$

$=0.3445783-0.2236273=0.120951\approx0.1210$

In percent , $0.1210\times100=12.10\%$

Hence, the percentage of days had a low temperature between 5 degrees and 10 degrees = 12.10%

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2 years ago

1 slope y-intercept equation o 6 5 4 3 2 2 3 5 j-intercept

mars1129 [50]

Answer:

Step-by-step explanation:

(-1,1) and (0,-2) are points on the line

slope of line = (-2-1)/(0-(-1)) = -3

y-intercept = -2

y = -3x - 2

3 0

2 years ago