Answer:
Hope it helps you :)
And i hope you understand
For store 1, it can be placed on 16 sites. Store 2 can be placed on 15 sites( since store 1 is already on site 1). Store 3 can be placed on 14 sites and so on until store 5 which has 12 sites.
Therefore the number of way is
C= 16*15*14*13*12
c=524,160 possibilities
Answer:
Going up by odd numbers I’m pretty sure
Step-by-step explanation:
1-2 that went up once
2-5 that went up 3 times
5-10 that went up 5
and so on
Using the numbers you have :
6 to -2
-2 to 2
4 to 1
-1 to 1
This is a function.
An input can only have one output, but an output can have multiple inputs.
![\bf \qquad \textit{Amount for Exponential Growth}\\\\ A=I(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\\ I=\textit{initial amount}\\ r=rate\to r\%\to \frac{r}{100}\\ t=\textit{elapsed time}\\ \end{cases}\\\\ -------------------------------\\\\ P(x)=3.113(1.2795)^x\implies \stackrel{A}{P(x)}=\stackrel{I}{3.113}(1+\stackrel{r}{0.2795})^{\stackrel{t}{x}}](https://tex.z-dn.net/?f=%5Cbf%20%5Cqquad%20%5Ctextit%7BAmount%20for%20Exponential%20Growth%7D%5C%5C%5C%5C%0AA%3DI%281%20%2B%20r%29%5Et%5Cqquad%20%0A%5Cbegin%7Bcases%7D%0AA%3D%5Ctextit%7Baccumulated%20amount%7D%5C%5C%0AI%3D%5Ctextit%7Binitial%20amount%7D%5C%5C%0Ar%3Drate%5Cto%20r%5C%25%5Cto%20%5Cfrac%7Br%7D%7B100%7D%5C%5C%0At%3D%5Ctextit%7Belapsed%20time%7D%5C%5C%0A%5Cend%7Bcases%7D%5C%5C%5C%5C%0A-------------------------------%5C%5C%5C%5C%0AP%28x%29%3D3.113%281.2795%29%5Ex%5Cimplies%20%5Cstackrel%7BA%7D%7BP%28x%29%7D%3D%5Cstackrel%7BI%7D%7B3.113%7D%281%2B%5Cstackrel%7Br%7D%7B0.2795%7D%29%5E%7B%5Cstackrel%7Bt%7D%7Bx%7D%7D)
usually, the "r" above, is used as a "rate of increase".
but 1+r combined, can be referred as the "rate for the new size".
so, for example, if something is increasing at a rate of 25%, 1+0.25 or 1.25, the new size wil be 1.25 or 125% of the old size.
Answer:
36
Step-by-step explanation:
you add the first two the order of operations then you do big and little