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Greeley [361]
3 years ago
10

A department store chain is expanding into a new market, and is considering 13 different sites on which to locate 5 stores. Assu

ming that each site is equally likely to be chosen, in how many ways can the sites for the new stores be selected?
Mathematics
1 answer:
Zepler [3.9K]3 years ago
8 0

Answer:

Hope it helps you :)

And i hope you understand  

For store 1, it can be placed on 16 sites. Store 2 can be placed on 15 sites( since store 1 is already on site 1). Store 3 can be placed on 14 sites and so on until store 5 which has 12 sites.

Therefore the number of way is

C= 16*15*14*13*12

c=524,160 possibilities

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90 x Y=450<br> What does Y equal
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Answer:

\Large \boxed{Y=5}

Step-by-step explanation:

\textnormal{First, divide by 90 from both sides of the equation.}

\displaystyle \frac{90y}{90}=\frac{450}{90}

\textnormal{Solve to find the answer.}

\displaystyle 450\div90=5

\displaystyle y=5, which is our answer.

Hope this helps!

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3 0
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Step-by-step explanation:

The answer is the second choice.  The outcome from rolling a fair die does not affect the outcome of drawing from a well-shuffled deck.  The probability of rolling a 5 will always be 1/6, and the probability of drawing an Ace will always be 4/52.

On the other hand, the weather of a city can depend on the weather from the previous day.

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