Ok <span>One side would have a length of 4, another side would have a length of 5, and then we can use the Pythagorean Theorem to find the length of the hypotenuse. a^2 + b^2 = c^2 </span>
<span>a=4; b=5; </span>
<span>4^2 + 5^2 = c^2 </span>
<span>16 + 25 = c^2 </span>
<span>41 = c^2 </span>
<span>c = √41 </span>
<span>Therefore, the hypotenuse has a length of √41. </span>
<span>To find the sinθ, you take the opposite over the hypotenuse. </span>
<span>Remember when you drew out the triangle? θ is the angle connected to the origin. The opposite side is b, which is 5. </span>
<span>Your answer is 5/√41. </span>
<span>This answer must be simplified since there is a radical in the denominator. To simplify, you can just multiply the numerator and the denominator by √41/√41 (since this is equivalent to 1). </span>
<span>This gives you the answer
</span>
Answer:
Three angles all equal is one equal triangle I pretty sure of this
Step-by-step explanation:
Answer:
3600
Step-by-step explanation:
Since the question gives you p, you replace p (which is just a placeholder) with 5.
Your equation should look like this:

Answer:
y = 6/5 x-1 slope intercept form
6x-5y = 5 standard form
Step-by-step explanation:
We have the points (0,-1) and (-5,-7)
We can find the slope using
m = (y2-y1)/(x2-x1)
= (-7--1)/(-5-0)
= (-7+1)/(-5-0)
= -6/-5
= 6/5
We also have the y intercept ( when x=0) It is -1
We can use the slope intercept form of the equation y = mx+b
y = 6/5 x-1
Depending on what you mean when you say simplify your answer
We can put it in standard form ax+by = C
Multiply both sides by 5
5y =5* 6/5 x-1*5
5y = 6x-5
Subtract 6x from each side
-6x+5y = 6x-6x-5
-6x+5y = -5
Multiply by -1
6x-5y = 5
let's recall that a cube is just a rectangular prism with all equal sides, check picture below.
![\bf \textit{volume of a cube}\\\\ V=s^3~~ \begin{cases} s=&length~of\\ &a~side\\ \cline{1-2} V=&27000 \end{cases}\implies 27000=s^3\implies \sqrt[3]{27000}=s\implies 30=s \\\\[-0.35em] ~\dotfill\\\\ \textit{surface area of a cube}\\\\ SA=6s~~\begin{cases} s=&length~of\\ &a~side\\ \cline{1-2} s=&30 \end{cases}\implies SA=6(30)\implies SA=180](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvolume%20of%20a%20cube%7D%5C%5C%5C%5C%20V%3Ds%5E3~~%20%5Cbegin%7Bcases%7D%20s%3D%26length~of%5C%5C%20%26a~side%5C%5C%20%5Ccline%7B1-2%7D%20V%3D%2627000%20%5Cend%7Bcases%7D%5Cimplies%2027000%3Ds%5E3%5Cimplies%20%5Csqrt%5B3%5D%7B27000%7D%3Ds%5Cimplies%2030%3Ds%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ctextit%7Bsurface%20area%20of%20a%20cube%7D%5C%5C%5C%5C%20SA%3D6s~~%5Cbegin%7Bcases%7D%20s%3D%26length~of%5C%5C%20%26a~side%5C%5C%20%5Ccline%7B1-2%7D%20s%3D%2630%20%5Cend%7Bcases%7D%5Cimplies%20SA%3D6%2830%29%5Cimplies%20SA%3D180)