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Tems11 [23]
3 years ago
14

Given the ordered pair P, determine the requested sin, cos, or tan of angle . P(4, 5) sin = (4√41)/41 (5√41)/41 4/5 5/4 what is

the correct answer
Mathematics
1 answer:
Viefleur [7K]3 years ago
6 0
Ok <span>One side would have a length of 4, another side would have a length of 5, and then we can use the Pythagorean Theorem to find the length of the hypotenuse. a^2 + b^2 = c^2 </span>

<span>a=4; b=5; </span>

<span>4^2 + 5^2 = c^2 </span>
<span>16 + 25 = c^2 </span>
<span>41 = c^2 </span>
<span>c = √41 </span>

<span>Therefore, the hypotenuse has a length of √41. </span>

<span>To find the sinθ, you take the opposite over the hypotenuse. </span>

<span>Remember when you drew out the triangle? θ is the angle connected to the origin. The opposite side is b, which is 5. </span>

<span>Your answer is 5/√41. </span>

<span>This answer must be simplified since there is a radical in the denominator. To simplify, you can just multiply the numerator and the denominator by √41/√41 (since this is equivalent to 1). </span>

<span>This gives you the answer

</span>
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Step-by-step explanation:

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Read 2 more answers
An upper triangular matric is square matrix with all zeros below its daignal. A lower triangular matrix is a square matrix with
AleksandrR [38]

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U₂₁ and U₂₂ fits in the line of upper triangular

Step-by-step explanation:

As explain in the question

An upper triangular matric is square matrix with all zeros below its daignal. A lower triangular matrix is a square matrix with all zeros above its diagonal.

(as shown in the attached image)

(a)for all 3×3 upper triangular matirices U, verify that U2 is also upper triangular

for a matrices U (having a 3*3 matrix), assuming for example, U is given below:

U = \left[\begin{array}{ccc}1&2&3\\0&5&6\\0&0&9\end{array}\right]

the element in the upper triangular are 1,2,3,5,6,9 (U₁₁, U₁₂, U₁₃; , U₂₂, U₂₃, U₂₂)

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