Choose the system of inequalities that best matches the graph below

In the equation, 1/4n+5=51/2 what is n equal to?

BlackZzzverrR [31]

Answer:

N = 2

Step-by-step explanation:

5 1/2 - 5

= 1/2

1/2 divided by 1/4 = 2

N = 2

5 0

3 years ago

Read 2 more answers

The tensile strength of stainless steel produced by a plant has been stable for a long time with a mean of 72 kg/mm2 and a stand

Elanso [62]

Answer:

95% confidence interval for the mean of tensile strength after the machine was adjusted is [73.68 kg/mm2 , 74.88 kg/mm2].

Yes, this data suggest that the tensile strength was changed after the adjustment.

Step-by-step explanation:

We are given that the tensile strength of stainless steel produced by a plant has been stable for a long time with a mean of 72 kg/mm 2 and a standard deviation of 2.15.

A machine was recently adjusted and a sample of 50 items were taken to determine if the mean tensile strength has changed. The mean of this sample is 74.28. Assume that the standard deviation did not change because of the adjustment to the machine.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean strength of 50 items = 74.28

$\sigma$ = population standard deviation = 2.15

n = sample of items = 50

$\mu$ = population mean tensile strength after machine was adjusted

Here for constructing 95% confidence interval we have used One-sample z test statistics as we know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level of

significance are -1.96 & 1.96}

P(-1.96 < $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $74.28-1.96 \times {\frac{2.15}{\sqrt{50} } }$ , $74.28+1.96 \times {\frac{2.15}{\sqrt{50} } }$ ]

= [73.68 kg/mm2 , 74.88 kg/mm2]

Therefore, 95% confidence interval for the mean of tensile strength after the machine was adjusted is [73.68 kg/mm2 , 74.88 kg/mm2].

Yes, this data suggest that the tensile strength was changed after the adjustment as earlier the mean tensile strength was 72 kg/mm2 and now the mean strength lies between 73.68 kg/mm2 and 74.88 kg/mm2 after adjustment.

8 0

3 years ago

Supriya invested $14,320 in a highly rated ETF. At the end of four years, she had $18,434. What was her annual effective yield o

adoni [48]

Answer:

6.517%

Step-by-step explanation:

This is a multi-year investment and we are not working with a $1 initial investment. There is no mention of compounding so we will use formula A=P0⋅(1+r)N with A=$18,434 and P0=$14,320. We do not know the value of r. However, N=4 years. Substituting the values we have $18,434=$14,320⋅(1+r)4. Divide both sides of the equation by $14,320. Next, take the fourth root of both sides of the equation and subtract 1 to find the decimal form of r.

$18,4341.287291.065170.06517=$14,320⋅(1+r)4=(1+r)4=1+r=r

Finally, convert r to a percent.

r=0.06517×100%=6.517%

6 0

3 years ago

Will give brainliest please show your work

Oksanka [162]

Answer:

Step-by-step explanation:

For surface area you wanna find the area of all the sides and then add them up to get surface area

5 0

2 years ago

Read 2 more answers

Find the co-ordinates of the points where the line represented by the linear equationy = 2x -4 intersects x-axis and y-axis.

nikdorinn [45]

Step-by-step explanation:

x-intercept => point (2, 0)

y-intercept => point (0, -4)

8 0

3 years ago