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arsen [322]
2 years ago
14

4

Mathematics
1 answer:
Helen [10]2 years ago
6 0

Answer:

y-intercept is (0, -4)

x-intercept is (-5, 0)

Step-by-step explanation:

Remember the x-intercept and the y-intercept are the points on the graph where the line crosses the x-axis and the y-axis respectively.

We can find the x intercept and the y intercept a couple of ways. One way is to graph the line, which I will do later. The other way is to do a little math.

The equation of a line in y-intercept form is

y = mx + b

where b = the y-intercept

In our equation above and solving for y we get the y-intercept is -4

4x + 5y =  - 20 \\ 5y =  - 4x - 20 \\ y =  -  \frac{4}{5} x - 4

Doing more algebra and solving for x we get the x intercept is negative 5.

y =  -  \frac{4}{5}  - 4 \\ y  + 4 =  -  \frac{4}{5} x \\ x =  -  \frac{5}{4} y -  \frac{20}{4 }  \\ x =  -  \frac{5}{4} y - 5

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A class consists of 17 men and 14 women. An exam is given andstudents are ranked according to their performance. Assume notwo st
notsponge [240]

Answer:

3.18%

Step-by-step explanation:

(14/31) X (13/30)X (12/29) X (11/28) = 0.0318 = 3.18%

5 0
3 years ago
Given f(x) =3x-7, find f(x+1)+f(1)
ELEN [110]

Answer:

3x - 8

Step-by-step explanation:

To find f(x + 1) substitute x = x + 1 into f(x)

f(x + 1) = 3(x + 1) - 7 = 3x + 3 - 7 = 3x - 4

Similarly

f(1) = 3(1) - 7 = 3 - 7 = - 4

Hence

f(x + 1) + f(1) = 3x - 4 - 4 = 3x - 8

3 0
3 years ago
A spacecraft is traveling with a velocity of v0x = 5320 m/s along the +x direction. Two engines are turned on for a time of 739
OlgaM077 [116]

Answer:

The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction

Step-by-step explanation:

  1. For a constant acceleration: v_{f}=v_{0}+at, where  v_{f} is the final velocity in a direction after the acceleration is applied, v_{0} is the initial velocity in that direction  before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied.
  2. <em>Then for the x direction</em> it is known that the initial velocity is v_{0x} = 5320 m/s, the acceleration (the applied by the engine) in x direction is a_{x} 1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the  is 739 s. Then: v_{fx}=v_{0x}+a_{x}t=5320\frac{m}{s} +1.79\frac{m}{s^{2} }*739s=6642.81\frac{m}{s}
  3. In the same fashion, <em>for the y direction</em>, the initial velocity is  v_{0y} = 0 m/s, the acceleration in y direction is a_{y} 7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: v_{fy}=v_{0y}+a_{y}t=0\frac{m}{s} +7.18\frac{m}{s^{2} }*739s=5306.02\frac{m}{s}
8 0
3 years ago
A group of church members chartered a bus for $832. After making the arrangements, 6 more members decided to join the excursion
g100num [7]
Let x = # of original members
Cost per person (originally) = 832/x
Cost per person after 6 more people = 832/(x+6)
Solve 832/x=832/(x+6) +6  (because the cost was reduced by 6 
Solve for x.
x = 26 or -32 (but x is number of members, so it can't be negative)
# of original members is 26.
Original cost is 832/26 = $32 per person.
3 0
2 years ago
Solve for X.<br><br> 2<br> 5<br> 25<br> 75
shtirl [24]
I don’t know honestly
5 0
2 years ago
Read 2 more answers
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