37. complementary angles always add up to 90. just subtract 57 from 90 and you get 37.
First of all, you have to send the measurements; otherwise, there would not be an answer
Answer:
what am i sopposed to do?
Step-by-step explanation:
Answer: Our required probability is 0.618.
Step-by-step explanation:
Since we have given that
Probability of all drivers were involved in a car accident last year = 66%
Number of drivers = 10
Number of drivers involved in a car accident = 3
So, probability of drivers involved in car accident is given by
![\dfrac{3}{10}\\\\=0.3](https://tex.z-dn.net/?f=%5Cdfrac%7B3%7D%7B10%7D%5C%5C%5C%5C%3D0.3)
Probability of getting 3 or more who were involved in a car accident is given by
P(X≥3)=1-P(X=0)-P(X=1)-P(X=2)
Here,
![P(X=0)=^{10}C_0(0.7)^{10}=0.028\\\\P(X=1)=^{10}C_1(0.7)^9(0.3)=0.121\\\\P(X=2)=^{10}C_2(0.7)^8(0.3)^2=0.233](https://tex.z-dn.net/?f=P%28X%3D0%29%3D%5E%7B10%7DC_0%280.7%29%5E%7B10%7D%3D0.028%5C%5C%5C%5CP%28X%3D1%29%3D%5E%7B10%7DC_1%280.7%29%5E9%280.3%29%3D0.121%5C%5C%5C%5CP%28X%3D2%29%3D%5E%7B10%7DC_2%280.7%29%5E8%280.3%29%5E2%3D0.233)
So, our equation becomes
P(X≥3)=1-P(X=0)-P(X=1)-P(X=2)
![P(X\geq 3)=1-0.028-0.121-0.233=0.618](https://tex.z-dn.net/?f=P%28X%5Cgeq%203%29%3D1-0.028-0.121-0.233%3D0.618)
Hence, our required probability is 0.618.
So, how much acid is there in 6 gallons? well is 20% acid or (20/100), so the amount of acid in it just (20/100) * 6 or 1.2, the rest is say water.
now, if we want a 90% solution, and say we add "y" gallons, how much acid is in it? well (90/100) * y, or 0.9y.
now let's add "x" gallons of pure acid, now, pure acid is just pure acid, so is 100% acid, how much acid is there in it? (100/100) * x, or 1x or just x.
we know whatever "x" and "y" amounts are, they -> x + 6 = y
and we also know that x + 1.2 = 0.9y