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3 years ago

PLS HELP ME UNDERSTAND THIS quUESTION!!

Mathematics

1 answer:

Mkey [24]3 years ago

6 0

Answer:

-2 11/35

Step-by-step explanation:

Hope it helps :)

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Over a three-week period, Abram spent 15

denis23 [38]

Answer:

20 hours

Step-by-step explanation:

First off, if we divide the number of hours he has played by the number of weeks 15/3 =

It would be an average of 5 hours per week

Therefore, in the next 4 weeks we would practice for 20 more hours.

i hope this helps you<33

have a nice day or night

7 0

3 years ago

The sum of two numbers is 25. One of the numbers is fifteen less than the other. Find the numbers.

bija089 [108]

20+5 because 5 is 15 less than 25.

4 0

4 years ago

Read 2 more answers

Solve y′′=sin(x) if y(0)=0 and y′(0)=5. y(x)=?

Ksenya-84 [330]

Answer:

$y(x)=6x-sin(x)$

Step-by-step explanation:

Rewrite the differential equation as:

$\frac{d^{2} y }{dx^{2} } =sin(x)$

Integrate both sides with respect to x:

$\int\ \frac{d^{2} y }{dx^{2} } dx = \int\ sin(x) dx$

$\frac{dy}{dx} =-cos(x)+C_1$

Integrate one more time both sides with respect to x:

$\int\ \frac{dy}{dx} = \int\ -cos(x)+C_1 dx$

$y(x)=-sin(x)+C_1x+C_2$

Now that we find the solution, let's find its derivate:

$y'(x)=C_1-cos(x)$

Evaluating the initial conditions:

$y(0)=C_1(0)+C_2-sin(0)=0\\C_2=0$

$y'(0)=C_1-cos(0)=5\\C_1=5+1=6$

Replacing the value of the constants that we found in the differential equation solution:

$y(x)=6x-sin(x)$

6 0

3 years ago

490,612 round to the nearest hundred thousand

ZanzabumX [31]

Answer:

500,000

Step-by-step explanation:

If the number is under 5 it rounds down and over 5 rounds up

3 0

3 years ago

Read 2 more answers

Find the equation of the tangent line to the curve 2exy=x+y at (0,2).

DiKsa [7]

Answer:

The equation of the tangent line to the curve

3 x - y = 2

Step-by-step explanation:

Step(i):-

Given function = f(x,y) = $2e^{xy} -x-y=0$ ...(i)

Differentiating equation (i) with respective to 'x' , we get

$2 e^{xy} \frac{d}{d x} (x y) -1 -\frac{dy}{dx} =0$

apply formula

$\frac{d}{dx} (UV) = UV^{l} +V U^{l}$

step(ii):-

⇒ $2 e^{xy} (x(\frac{d}{d x} ( y))+y(1)) -1 -\frac{dy}{dx} =0$

⇒ $2 e^{xy} (x(\frac{d}{d x} ( y))+ 2e^{xy} y(1)) -1 -\frac{dy}{dx} =0$

Taking common d y/d x

$(2 e^{xy} (x) -1)\frac{dy}{dx} =1- 2e^{x y} y(1))$

$\frac{dy}{dx} =\frac{1- 2e^{x y} y(1))}{(2 e^{xy} (x) -1)}$

put At (0,2)

$\frac{dy}{dx} =\frac{1- 2e^{0} 2(1))}{(2 e^{0} (0) -1)}=\frac{1-4}{-1} =3$

slope of the curve m = 3

Step(iii):-

The equation of the tangent line to the curve

$y-y_{1} =m(x-x_{1} )$

y - 2 = 3 ( x - 0 )

3 x - y = 2

Final answer:-

The equation of the tangent line to the curve

3 x - y = 2

8 0

3 years ago