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2 years ago

9

In a dog show, how many ways can 3 beagles, 2 poodles, and 5 grey hounds line up if the dogs of the same breed are considered id

entical?

1 answer:

Tema [17]2 years ago

6 0

Answer:

30

Step-by-step explanation:

3 x 2 x 5 equals 30

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Y plus 4 plus 3(y plus 2)

Serga [27]

Answer:

5y+11

Step-by-step explanation:

y+3+4(y+2)

Use the distributive property to multiply 4 by y+2.

y+3+4y+8

Combine y and 4y to get 5y.

5y+3+8

Add 3 and 8 to get 11.

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1 year ago

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Which gives the line of best fit?

BartSMP [9]

Answer:

B

Step-by-step explanation:

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2 years ago

Write as a single power of 8.<br> 8 to the power of 8<br><br> ÷<br> 8 to the power of 2

OLEGan [10]

Answer: 8^6

Step-by-step explanation:

$\frac{8^8}{8^2}$ = $8^{6}$ subtract the bottom exponent from the top exponent.

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2 years ago

Question 3<br> And question 4 pleaseeee help!!

Verizon [17]

Answer:

see pdf

Step-by-step explanation:

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2 years ago

Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III

vodka [1.7K]

Given:

$\sin x=-\dfrac{15}{17}$

x lies in the III quadrant.

To find:

The values of $\sin 2x, \cos 2x, \tan 2x$ .

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others are negative.

We know that,

$\sin^2 x+\cos^2 x=1$

$(-\dfrac{15}{17})^2+\cos^2 x=1$

$\cos^2 x=1-\dfrac{225}{289}$

$\cos x=\pm\sqrt{\dfrac{289-225}{289}}$

x lies in the III quadrant. So,

$\cos x=-\sqrt{\dfrac{64}{289}}$

$\cos x=-\dfrac{8}{17}$

Now,

$\sin 2x=2\sin x\cos x$

$\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})$

$\sin 2x=-\dfrac{240}{289}$

And,

$\cos 2x=1-2\sin^2x$

$\cos 2x=1-2(-\dfrac{15}{17})^2$

$\cos 2x=1-2(\dfrac{225}{289})$

$\cos 2x=\dfrac{289-450}{289}$

$\cos 2x=-\dfrac{161}{289}$

We know that,

$\tan 2x=\dfrac{\sin 2x}{\cos 2x}$

$\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}$

$\tan 2x=\dfrac{240}{161}$

Therefore, the required values are $\sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}$ .

7 0

2 years ago