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madreJ [45]
2 years ago
5

The Pipeline Plunge is reflected across the

Mathematics
1 answer:
scoray [572]2 years ago
8 0

Answer:

?

Step-by-step explanation:

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Does (2,0) work as a solution to the systems of equations to lines 3x+y=6 and 3x-y=6
fenix001 [56]

Answer:

Yes

Step-by-step explanation:

To see if (2,0) works as a solution to the systems of equations, we plug in the values of x and y and simplify. If the results are equal, then (2,0) is a solution.

3x + y = 6:

  • 3(2) + 0 = 6
  • 6 + 0 = 6
  • 6 = 6
  • (2,0) is a solution to this equation.

3x - y = 6:

  • 3(2) - 0 = 6
  • 6 - 0 = 6
  • 6 = 6
  • (2,0) is a solution to this equation.

Therefore, the answer is yes, it does work as a solution.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

7 0
2 years ago
Which is the approximate solution to the system y = 0.5x + 3.5 and y = − 2/3 x + 1/3 shown on the graph? (–2.7, 2.1) (–2.1, 2.7)
AlekseyPX

Answer:

The approximate solution to the system is (-2.7, 2.1).

Step-by-step explanation:

To solve the system of equations \begin{bmatrix}y=0.5x+3.5\\ y=-\frac{2}{3}x+\frac{1}{3}\end{bmatrix} you must:

\mathrm{Rationalize\:equations}\\\\\begin{bmatrix}y=\left(\frac{1}{2}\right)x+\left(\frac{7}{2}\right)\\ y=-\frac{2}{3}x+\frac{1}{3}\end{bmatrix}

\mathrm{Subsititute\:}y=-\frac{2}{3}x+\frac{1}{3}\\\\\begin{bmatrix}-\frac{2}{3}x+\frac{1}{3}=\frac{1}{2}x+\frac{7}{2}\end{bmatrix}

\mathrm{Isolate}\:x\:\mathrm{for}\:-\frac{2}{3}x+\frac{1}{3}=\frac{1}{2}x+\frac{7}{2}\\\\-\frac{2}{3}x=\frac{19}{6}+\frac{1}{2}x\\\\-\frac{7}{6}x=\frac{19}{6}\\\\6\left(-\frac{7}{6}x\right)=\frac{19\cdot \:6}{6}\\\\-7x=19\\\\x=-\frac{19}{7}\approx-2.7

\mathrm{For\:}y=-\frac{2}{3}x+\frac{1}{3}\\\\\mathrm{Subsititute\:}x=-\frac{19}{7}\\\\y=-\frac{2}{3}\left(-\frac{19}{7}\right)+\frac{1}{3}\\\\y=\frac{15}{7}\approx 2.1

The approximate solutions to the system of equations are:

x=-2.7 ,\:y=2.1

5 0
3 years ago
Read 2 more answers
What is the measure of angle D?<br> A. 75°<br> B. 80°<br> C. 95°<br> D. 110°
lana66690 [7]

Answer:

110%

Explanation:

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8 0
3 years ago
Solve the problem using the six-step method: A pharmacist found at the end of the day she had 7/4 as many prescriptions for anti
svet-max [94.6K]
<h3>Given</h3>

1 (female) pharmacist counting prescriptions at the end of the day

(prescriptions for antibiotics) = (7/4)×(prescriptions for tranquilizers)

33 = (prescriptions for tranquilizers) + (prescriptions for antibiotics)

<h3>Find</h3>

The number of (prescriptions for tranquilizers)

<h3>Solution</h3>

Let <em>x</em> represent the number of <em>prescriptions for tranquilizers</em>. Then the number of prescriptions for antibiotics is (7/4)x, and the total number of prescriptions is

... 33 = x + (7/4)x . . . . . . . . . . put the given information in the given relation

... 33 = (4/4)x + (7/4)x . . . . . . rewrite 1 as 4/4 so we can add to 7/4

... 33 = ((4+7)/4)x = (11/4)x . . . simplify

... 33×(4/11) = (4/11)×(11/4)x . . . multiply by the reciprocal of the coefficient of x

... 12 = x . . . . . . . . . . . . . . . . . simplify

The pharmacist had 12 prescriptions for tranquilizers.

The pharmacist had 33-12 = 21 prescriptions for antibiotics.

There was 1 pharmacist and 33 prescriptions.

7 0
3 years ago
Converges and diverged part 4<br>​
Allushta [10]

Answer:

Diverges; no sum

Step-by-step explanation:

This is comparable to:

\sum_{k=1}^\infty a \cdot r^{k-1} where:

r is the common ratio and a is the first term.

The series converges to:

\text{First term}\cdot \frac{1}{1-\text{common ratio}}

if the ratio's absolute value is less than 1.

This is a geometric series.

The common ration is -1.04 .

The first term in the series is 0.001.

Since the absolute value of -1.04 is 1.04>1, the series diverges.

4 0
3 years ago
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