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Lera25 [3.4K]
4 years ago
15

A piece of chocolate is 4/5 inch long. Meg lays 4 chocolate pieces end to end in a row. How many inches long is the row of choco

lates ( please helpppppp) ( MAP test question)
Mathematics
1 answer:
almond37 [142]4 years ago
7 0

Answer:

The length of row = 3.2 inches.

Step-by-step explanation:

The length of a chocolate = 4/5 inch

Total number of chocolate pieces placed = 4

Now we have given the length of one chocolate and it is required to find the total length of the row when four chocolates are placed end to end. So in order to find the length of the chocolate row we have to multiply the size of one chocolate by the number of chocolates.

The length of row = Length of one chocolate × number of chocolates

The length of row = 4/5 × 4

The length of row = 3.2 inches.

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3 years ago
14x + 6 = 5x - 3 with solution
Schach [20]

hey there

the answer is

14x + 6 = 5x + -3


6 + 14x = 5x + -5

6 + 14x = -3 + 5x


6 + 14x + -5x = -3 + 5x + -5x


Combine like terms: 14x + -5x = 9x

6 + 9x = -3 + 5x + -5x


Combine like terms: 5x + -5x = 0

6 + 9x = -3 + 0

6 + 9x = -3

6 + -6 + 9x = -3 + -6


Combine like terms: 6 + -6 = 0

0 + 9x = -3 + -6

9x = -3 + -6


Combine like terms: -3 + -6 = -9

9x = -9


Divide each side by '9'.

x = -1


Simplifying

x = -1

thank you

OFFICIALLYSAVAGE2003

5 0
4 years ago
What is the interquartile range of the data ? 0,2,4,0,2,3,8,6
Alexeev081 [22]

(arrange the data set from least to greatest)

0, 0, 2, 2, 3, 4, 6, 8

(find the median: *the middle number*)

Median: 2.5

Lower quartile: 1

Upper quartile: 5

Interquartile range : upper quartile - lower quartile = answer

Interquartile range: 5 - 1 = 4

So the IQR or interquartile for the following data set is 4.

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3 years ago
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