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AfilCa [17]
3 years ago
6

“Place brackets to make the statement true.”

Mathematics
1 answer:
Fittoniya [83]3 years ago
6 0

Step-by-step explanation:

please mark me as brainlest

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Need help ASAP DUE IN ONE DAY thanks
erastovalidia [21]

Answer:

(5k+14)(3k+8)

Step-by-step explanation:

7 0
3 years ago
I need to graduate please.<br>Which expression is a perfect cube?<br> x^8<br> y^24<br> m^26<br> s^64
myrzilka [38]
Remember
(a^b)^c=a^{bc}

note that if a^3 is a perfect cube then (a^3)^c is also a perfect cube when c is an integer

(a^3)^c=a^{3c}
so if a number is a perfect cube then the power must be divisible by 3

8 is not divisible by 3
24 is divisible by 3
26 is not divisibley by 3
64 is not divisible by 3

the perfect cube is y^24
8 0
3 years ago
46 degrees (4x) degrees
motikmotik

Answer:

whats your question im confused

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Solve 5x^2 − 3x + 17 = 9.
Vedmedyk [2.9K]

Answer:

The roots of the equation are x = \frac{3+\sqrt{151}i}{10} and x = \frac{3-\sqrt{151}i}{10}

and there are no real roots of the equation given above

Step-by-step explanation:

To solve:

5x² − 3x + 17 = 9

or

⇒ 5x² − 3x + 17 - 9 = 0

or

⇒ 5x² − 3x + 8 = 0

Now,

the roots of the equation in the form ax² + bx + c = 0 is given as:

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

in the above given equation

a = 5

b = -3

c = 8

therefore,

x = \frac{-(-3)\pm\sqrt{(-3)^2-4\times5\times8}}{2\times5}

or

x = \frac{3\pm\sqrt{9-160}}{10}

or

x = \frac{3+\sqrt{-151}}{10} and x = \frac{3-\sqrt{-151}}{10}

or

x = \frac{3+\sqrt{151}i}{10} and x = \frac{3-\sqrt{151}i}{10}

here i = √(-1)

Hence,

The roots of the equation are x = \frac{3+\sqrt{151}i}{10} and x = \frac{3-\sqrt{151}i}{10}

and there are no real roots of the equation given above

7 0
3 years ago
Draw a model to subtract 2 2/5 -1 8/10
Igoryamba

See picture for reply and solution steps.

6 0
3 years ago
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