Question

One positive number is 8 more than twice another. If their product is 234 find the numbers

Answer 1

Answer:

Step-by-step explanation:

Let the larger number = x

Let the smaller number = y

x = 2*y + 8

x * y = 234              Put the first  equation into the second.

(2y + 8)*y = 234      Remove the brackets

2y^2 + 8y = 234     Subtract 234 from both sides

2y^2 +  8y - 234 =0 Factor out 2

2(y^2 + 4y - 117) = 0 Divide by 2

y^2 + 4y - 117 = 0

(y + 13)(y - 9)

y = 9 is one answer

x * y = 234

x * 9 = 234         Divide by 9

x = 234/9

x = 26

The two numbers are 9 and 26