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liberstina [14]
3 years ago
12

What is the slope of each line? Line A: y = one-half x minus 4 Line B: y = 2 x minus 3 The slope of line A Equals one-half. The

slope of line B Equals 2. The slope of line A Equals negative 4. The slope of line B Equals negative 3. The slope of line A Equals negative one-half. The slope of line B Equals negative 2. The slope of line A Equals negative 3. The slope of line B Equals negative 4.
Mathematics
2 answers:
abruzzese [7]3 years ago
6 0

Answer:

A.

Step-by-step explanation:

I took the quiz

Anestetic [448]3 years ago
5 0

Answer:

The slope of line A equals one-half. The slope of line B equals 2.

Step-by-step explanation:

The equation of Line A is given by : y = \frac{1}{2} x - 4 ........... (1)

The equation of Line B is given by : y = 2x - 3 ............. (2)

Those two equations are in slope-intercept form i.e. y = mx + c, where m is the slope of the line.

Now, the slope of line A equals one-half. The slope of line B equals 2.

Therefore, option 1 will be correct. (Answer)

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Which translation maps the vertex of the graph of the function f(x) = x2 onto the vertex of the function g(x) = x2 + 2x +1?
jarptica [38.1K]

Answer:

Option B is correct

Left 1 unit.

Explanation:

According to the graph theory of transformation:

y = f(x+k)=\left \{ {{k>0 shift graph of y= f(x) left k unit} \atop {k

Given the parent function: f(x)=x^2

and the function g(x)=x^2+2x+1

we can write it as:

g(x)= (x+1)^2   [ ∴(a+b)^2 = a^2+2ab+b^2 ]

Therefore, vertex of the graph of the function g(x)=(x+1)^2 is 1 units to the left of the vertex of the graph of the function f(x)=x^2 .




6 0
3 years ago
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10x=5x2−1. Complete the square
vitfil [10]

Answer: I did the test too

4 0
1 year ago
If < 1 = 125, what is < 7?
nordsb [41]

Answer:

875

Step-by-step explanation:

125 x 7 = 875

5 0
2 years ago
Need Help Since Schoo is Closed
marishachu [46]

Answer:

32

Step-by-step explanation:

let a = 5

a² + 7 | Original equation

5² + 7 | Substitution of a as 5

25 + 7 | 5 to the power of 2 is 25, as 5*5 = 25.

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4 0
3 years ago
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A paperweight is shaped like a triangular pyramid. The base is an equilateral triangle. Find the surface area of the paperweight
stich3 [128]

Answer:

The surface area of the paperweight is SA=8.3\ in^2

Step-by-step explanation:

we know that

The surface area of the triangular prism is equal to the area of its triangular base plus the area of its three triangular lateral faces

so

<em>Find the area of its triangular base</em>

SA=\frac{1}{2}(2)(1.7)

SA=1.7\ in^2

<em>Find the area of its three triangular lateral faces</em>

SA=3[\frac{1}{2}(2)(2.2)]

SA=6.6\ in^2

Adds the areas

SA=1.7+6.6

SA=8.3\ in^2

4 0
3 years ago
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