Answer:
If we compare this value with the 47.3 proposed we have the following error
The computed mean is close to the actual mean because the difference between the means is less than 5%.
Step-by-step explanation:
Assuming the following dataset:
Speed 42-45 46-49 50-53 54-57 58-61
Freq. 21 15 6 4 2
And we are interested in find the mean, since we have grouped data the formula for the mean is given by:
And is useful construct a table like this one:
Speed Freq Midpoint Freq*Midpoint
42-45 21 43.5 913.5
46-49 15 47.5 712.5
50-53 6 51.5 309
54-57 4 55.5 222
58-61 2 59.5 119
Total 48 2276
And the mean is given by:
If we compare this value with the 47.3 proposed we have the following error
The computed mean is close to the actual mean because the difference between the means is less than 5%.
Answer:
Step-by-step explanation:
Given that:
Ava bring 34 food to the picnic
Kate bring 16 food to the picnic
JIn brings 112 food to the picnic
To enter these digits by applying equivalent fractions with a denominator of 12;
Their respective numerical expression is:
Ava = 
Ava brought 
food to the picnic
Kate = 
Kate brought 
food to the picnic
Jin = 
Jin brought 
food to the picnic
Answer:
odd
Step-by-step explanation:
i looked it up
Factor the following:
12 x^4 - 42 x^3 - 90 x^2
Factor 6 x^2 out of 12 x^4 - 42 x^3 - 90 x^2:
6 x^2 (2 x^2 - 7 x - 15)
Factor the quadratic 2 x^2 - 7 x - 15. The coefficient of x^2 is 2 and the constant term is -15. The product of 2 and -15 is -30. The factors of -30 which sum to -7 are 3 and -10. So 2 x^2 - 7 x - 15 = 2 x^2 - 10 x + 3 x - 15 = x (2 x + 3) - 5 (2 x + 3):
6 x^2 x (2 x + 3) - 5 (2 x + 3)
Factor 2 x + 3 from x (2 x + 3) - 5 (2 x + 3):
Answer: 6 x^2 (2 x + 3) (x - 5)
The equation is
8x +7=125
