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Airida [17]
2 years ago
7

What's the value of given expression :

sqrt{9} " alt=" \sqrt{9} " align="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
sdas [7]2 years ago
7 0

\sqrt{9}  = 3

\:

{\boxed{\sf{3 \times 3 = 9}}}

shusha [124]2 years ago
4 0

Answer:

\sqrt{9}  =  \sqrt{3 \times 3}  = 3 \\ thank \: you

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The answer is (3) 4896.

This number comes from multiplying 18 x 17 x 16

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3 years ago
Tim Worker decided to purchase a new DVD player on an installment loan. The DVD player was $295.00. Tim agreed to pay $31.00 per
Kryger [21]
Hi there

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5 0
2 years ago
Show step by step work ​
SOVA2 [1]

Answer:

$60

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3 0
2 years ago
The body temperatures of a group of healthy adults have a bell-shaped distribution with a mean of 98.35°F and a standard deviati
DochEvi [55]

Answer:

a) 99.97%

b) 65%

Step-by-step explanation:

• 68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ.

• 95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ.

• 99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ.

Mean of 98.35°F and a standard deviation of 0.64°F.

a. What is the approximate percentage of healthy adults with body temperatures within 3 standard deviations of the mean, or between 96.43°F and 100.27°F?

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98.35 - 3(0.64)

= 96.43°F

μ + 3σ.

98.35 + 3(0.64)

= 100.27°F

The approximate percentage of healthy adults with body temperatures is 99.97%

b. What is the approximate percentage of healthy adults with body temperatures between 97 .71°F and 98.99°F?

within 1 standard deviation from the mean - that means between μ - σ and μ + σ.

μ - σ

98.35 - (0.64)

= 97.71°F

μ + σ.

98.35 + (0.64)

= 98.99°F

Therefore, the approximate percentage of healthy adults with body temperatures between 97.71°F and 98.99°F is 65%

4 0
3 years ago
What is the solution to the following system of
Rufina [12.5K]

Answer:

i think the correct answer of these qusion is -2,3

5 0
2 years ago
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