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Airida [17]
3 years ago
7

What's the value of given expression :

sqrt{9} " alt=" \sqrt{9} " align="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
sdas [7]3 years ago
7 0

\sqrt{9}  = 3

\:

{\boxed{\sf{3 \times 3 = 9}}}

shusha [124]3 years ago
4 0

Answer:

\sqrt{9}  =  \sqrt{3 \times 3}  = 3 \\ thank \: you

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Find the answer pleaseeee...<br><br>-15/9 + 9/4 = ? <br><br>Please find what the question mark is​
SVEN [57.7K]

Answer:

7/12

Step-by-step explanation:

-15/9+9/4

We need to make them have the same denominator:

9x4= 36 so that is our new denominator

-15x4= -60

9x9=81

(Sorry if i dont make sense)

Now we have -60/36+81/36 which is equal to 21/36.

Now we simplify:

21/36=7/12

3 0
3 years ago
Calculation: One score is 20. Two score is 40. Three score and 5 is 65.
wariber [46]

Answer:

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3 years ago
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Doss [256]

Answer:

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Step-by-step explanation:

7 0
3 years ago
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Help me for brainlist no cap
Schach [20]

Answer:

C

Step-by-step explanation:

So first, you find the area of a rectangle, which would be 15 * 30 = 450. Next, find the area of the semicircle by doing \pi *r^2 / 2 (you have to divide by 2 because it's only have a circle).

The radius is half of 15, so 15 / 2 = 7.5. This would be:

\pi * 7.5^2 / 2

=\pi * 56.25 /2

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7 0
2 years ago
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What is the form of the Pythagorean triple generator?​
stepladder [879]

Answer:(x^2+y^2)^2=(x^2+y^2)(x^2+y^2)

Step-by-step explanation:

We can rewrite left side into right side form

(x^2+y^2)^2=(x^2+y^2)(x^2+y^2)

we can expand it

(x^2+y^2)^2=x^4+x^2y^2+x^2y^2+y^4

(x^2+y^2)^2=x^4+y^4+2x^2y^2

we can add and subtract 2x^2y^2

(x^2+y^2)^2=x^4+y^4+2x^2y^2+2x^2y^2-2x^2y^2

(x^2+y^2)^2=x^4-2x^2y^2+y^4+2x^2y^2+2x^2y^2

(x^2+y^2)^2=x^4-2x^2y^2+y^4+4x^2y^2

(x^2+y^2)^2=x^4-2x^2y^2+y^4+(2xy)^2

(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2

4 0
3 years ago
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