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Alexandra [31]
2 years ago
12

Does anyone know the answer

Mathematics
1 answer:
murzikaleks [220]2 years ago
6 0

Answer:

20,160

Step-by-step explanation:

You might be interested in
If a+b = 7, and a² +b²=25<br>then ab = ?​
Rama09 [41]

a2+b2=25

or, (a+b)^2-2ab=25

or, (7)^2-2ab=25 [a+b=7]

or, 49-25=2ab

or, 24/2=an

•°• ab=12....

3 0
3 years ago
(09.02)
dmitriy555 [2]
X^2 - 7x + 12 = 0
x^2 - 4x - 3x + 12 = 0
x (x - 4) -3 ( x - 4) = 0
(x - 4) (x - 3) = 0
x = 3 , 4

Check the answer by plugging in 3 and 4 for x, if the equation equals zero then you have your answer.
4 0
2 years ago
Solve for y -2(x + 3 y) =18
LUCKY_DIMON [66]

Answer:

y= -3y - 1/3x

Step-by-step explanation:

-2(x + 3y) = 18 Distribute the -2 to the x + 3y

-2x - 6y = 18

+2x          +2x    Add the 2x to both sides

-6y = 18 + 2x   Divide both sides by -6

y= -3y - 1/3x

3 0
3 years ago
Use the discriminate to determine the number and the nature of the solutions of the giving equation.
PolarNik [594]

Answer:

Since b^2 -4ac = 256 we have 2 real distinct root roots

Step-by-step explanation:

4x^2+12x=7

We need to subtract 7 to get it in the proper form

4x^2+12x-7=7-7

4x^2+12x-7=0

The discriminant is b^2 -4ac

when the equation is ax^2 +bx+c

so a =4   b=12 and c=-7

(12)^2 - 4(4)(-7)

144 +112

256

If b^2 -4ac > 0 we have 2 real distinct roots

If b^2 -4ac = 0 we have one real root

If b^2 -4ac < 0 we have two complex root

Since b^2 -4ac = 256 we have 2 real distinct root roots

7 0
3 years ago
Y=x-3 and y=-3x+25 in substitution form
Vlad1618 [11]
(x-3)=-3x+25

Because we know that y=x-3 so we put that in place of y in the equation
8 0
3 years ago
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