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Igoryamba
2 years ago
12

)x^{3}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Alex_Xolod [135]2 years ago
7 0

After talking with you here are two different options I think you are trying to ask:

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

If you are talking about: (\frac{-12}{3}) ^{3}

Answer: -62

Explanation:

PEMDAS tells us we need to do the exponent first:

-12³ = (-12)³ = -1728

<em>The parentheses are important so you cube the negative sign as well!</em>

3³ = 27

-1728 / 27 = -62

                           (\frac{-12}{3}) ^{3} simplified is -62

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

If you are talking about (-1\frac{2}{3})³

Answer: -\frac{125}{27}

Explanation:

First, let us turn -1 and two thirds into a mixed number:

Ignoring the negative for now, we can 1 times 3 is 3. 3 plus 2 is 5. 5/3 is 5/3. Adding in the negative we get -\frac{5}{3}

To cube it we must do:

(-\frac{5}{3})(-\frac{5}{3})(-\frac{5}{3})

3 times 3 (9) times 3 is 27

5 times 5 (25) times 5 is 125

So we have 125/27

For the negative, we have three - - -

Two cancel each other out, and we are left with one (-) so our answer is negative

                           (-1\frac{2}{3})³ simplifed is -\frac{125}{27}

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Estimate 0.067238149 to the nearest hundredth. Express your answer as a single digit times a
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Read 2 more answers
You have 100 cm of string which can be cut in one place (or not cut at all) and then formed into a circle and a square (or just
Ne4ueva [31]

Answer:

44cm for minimum area and 0 for maximum area (circle)

Step-by-step explanation:

Let's C be the circumference of the circle and S be the circumference of the square. If we cut the string into 2 pieces the total circumferences would be the string length 100cm.

S + C  = 100 or S = 100 - C

The side of square is S/4 and radius of the circle is \frac{C}{2\pi}

So the area of the square is

A_S = \frac{S^2}{4^2} = \frac{S^2}{16}

A_C = \pi\frac{C^2}{(2\pi)^2} = \frac{C^2}{4\pi}

Therefore the total area is

A = A_S + A_C = \frac{S^2}{16} + \frac{C^2}{4\pi}

We can substitute 100 - C for S

A = \frac{(100 - C)^2}{16} + \frac{C^2}{4\pi}

A = \frac{100^2 - 200C + C^2}{16} + \frac{C^2}{4\pi}

A = 625 -12.5C + \frac{C^2}{16} + \frac{C^2}{4\pi}

A = 625 -12.5C + C^2(\frac{1}{16} + \frac{1}{4\pi})

To find the maximum and minimum of this, we can take the first derivative and set that to 0

A^{'} = -12.5 + 2C(\frac{1}{16} + \frac{1}{4\pi}) = 0

C(\frac{1}{8} + \frac{1}{2\pi}) = 12.5

C \approx 44 cm

If we take the 2nd derivative:

A^{''} = \frac{1}{8} + \frac{1}{2\pi} > 0

We can see that this is positive, so our cut at 44 cm would yield the minimum area.

The maximum area would be where you not cut anything and use the total string length to use for either square or circle

if C = 100 then A_C = \frac{C^2}{4\pi} = \frac{100^2}{4\pi} = 795.77 cm^2

if S = 100 then A_S = \frac{S^2}{16} = \frac{100^2}{16} = 625 cm^2

So to yield maximum area, you should not cut at all and use the whole string to form a circle

4 0
3 years ago
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