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Igoryamba
2 years ago
12

)x^{3}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Alex_Xolod [135]2 years ago
7 0

After talking with you here are two different options I think you are trying to ask:

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

If you are talking about: (\frac{-12}{3}) ^{3}

Answer: -62

Explanation:

PEMDAS tells us we need to do the exponent first:

-12³ = (-12)³ = -1728

<em>The parentheses are important so you cube the negative sign as well!</em>

3³ = 27

-1728 / 27 = -62

                           (\frac{-12}{3}) ^{3} simplified is -62

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

If you are talking about (-1\frac{2}{3})³

Answer: -\frac{125}{27}

Explanation:

First, let us turn -1 and two thirds into a mixed number:

Ignoring the negative for now, we can 1 times 3 is 3. 3 plus 2 is 5. 5/3 is 5/3. Adding in the negative we get -\frac{5}{3}

To cube it we must do:

(-\frac{5}{3})(-\frac{5}{3})(-\frac{5}{3})

3 times 3 (9) times 3 is 27

5 times 5 (25) times 5 is 125

So we have 125/27

For the negative, we have three - - -

Two cancel each other out, and we are left with one (-) so our answer is negative

                           (-1\frac{2}{3})³ simplifed is -\frac{125}{27}

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Alekssandra [29.7K]
After 1.4 seconds, t = 1.4.
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3 0
3 years ago
suppose a parabola has an axis of symmetry at x = -8, a maximum height of 2, and passes through the point (-7, -1). Write the eq
lesya [120]

Answer:

<h3>            f(x) = - 3(x + 8)² + 2</h3>

Step-by-step explanation:

f(x) = a(x - h)² + k   - the vertex form of the quadratic function with vertex    (h, k)

the<u> axis of symmetry</u> at<u> x = -8</u> means h = -8

the <u>maximum height of 2</u> means  k = 2

So:

f(x) = a(x - (-8))² + 2

f(x) = a(x + 8)² + 2   - the vertex form of the quadratic function with vertex   (-8, 2)

The parabola passing through the point (-7, -1) means that if x = -7 then        f(x) = -1

so:

    -1 = a(-7 + 8)² + 2

 -1 -2 = a(1)² + 2 -2

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Threfore:

The vertex form of the parabola which has an axis of symmetry at x = -8, a maximum height of 2, and passes through the point (-7, -1) is:

                                 <u>f(x) = -3(x + 8)² + 2</u>

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3 years ago
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y = mx + b
slope(m) = -3
(3,-5)...x = 3 and y = -5
now we sub and find b, the y int
-5 = -3(3) + b
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