All categories

2 years ago

Hida adds 5 to a number, then multiplies the sum by-2. The result is 6. write an equation and solve for x

Mathematics

1 answer:

ella [17]2 years ago

7 0

Answer:

6 = -2(x+5)

6 = -2x -10

6 + 10 = -2x

16 = -2x

x = 16/-2

x = -8

You might be interested in

Solve for n. n + 1 = 4(n - 8) n = 1 T n = 8 n = 11 n = 16

Komok [63]

Answer:

n=11

Step-by-step explanation:

n+1=4(n-8)

11+1=4(11-8)

12=4(3)

12=12

3 0

2 years ago

Read 2 more answers

Roman buys seed packets for the school garden. One packet of radish seeds costs $1.75. One packet of tomato seeds costs $2.50. L

HACTEHA [7]

Answer:

C. $t=23,r=9$ .

Step-by-step explanation:

Let r represent the cost of one packet of radish seeds and let t represent the cost of one packet of tomato seeds.

Roman spent $62.75

This implies that,

$1.75r+2.5t=62.75...eqn1$

Roman bought 32 packets of seeds and one packet of radish seeds costs
$ 1.75.
One packet of tomato seeds costs $ 2.50.

This implies that,

$r+t=32...eqn2$

Using guess and check means we substitute into the given equation.

A) We substitute $t=8,r=24$ into both equations.

$1.75(8)+2.5(24)=62.75...eqn1$

$14+60\ne 62.75...eqn1$

$8+24=32...eqn2$

Both equations are not satisfied.

B)

We substitute $t=9,r=23$ into both equations.

$1.75(9)+2.5(23)=62.75...eqn1$

$15.75+57.5\ne 62.75...eqn1$

$9+23=32...eqn2$

Both equations are not satisfied.

C)

We substitute $t=23,r=9$ into both equations.

$1.75(23)+2.5(9)=62.75...eqn1$

$40.25+22.5 =62.75...eqn1$

$23+9=32...eqn2$

Both equations are satisfied.

Hence the solution is,

$t=23,r=9$

D) We substitute $t=24,r=8$ into both equations.

$1.75(24)+2.5(8)=62.75...eqn1$

$42+20\ne 62.75...eqn1$

$24+8=32...eqn2$

Both equations are not satisfied.

4 0

2 years ago

Read 2 more answers

Charisse is buying two different types of cereals from the bulk bins at the store. Granola costs $2.29 per pound and muesli cost

valentina_108 [34]

Even though im not giving you grapahs, I can explain you the situation and I can shed you light inot this. Pay attention. Giveen the data we are going to use it like this 2.29x + 3.75y <= 7.00. Remember, you can't spend more money than 7.00, so whatever you buy has to be within 7.00$ or equal 7.00$. Since you're buying in pounds, and the amount varies, you have a variable there to indicate the price of each product depending on how many pounds of it you buy. Now, what you need to do is use this equation to graph and also solving part b by substituting in that value for y. I hope this can help you

6 0

3 years ago

Find the range of ƒ(x) = 3g – 5 for the domain {–1.5, 2, 4}

timofeeve [1]

-1.5 ------ f(x) = 3(-1.5) - 5
= -4.5 -5
= 9.5

2 -------- f(x) = 3(2) - 5
= 6 -5
= 1

4 -------- f(x) = 3(4) - 5
= 12 - 5
= 7
(9.5, 1 , 7)

6 0

2 years ago

HELPP!! Select the correct answer. What is the value of arcsin ?

Schach [20]

For this case we have that by definition, it is called arcsine (arcsin) from a number to the angle that has that number as its sine.

We must find the $arcsin (\frac {\sqrt {2}} {2})$ . Then, we look for the angle whose sine is $\frac {\sqrt {2}} {2}$ .