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ludmilkaskok [199]

3 years ago

12

How do I graph a rational function with a y intercept. Example 3x^2-1/2x+4 +1

1 answer:

zloy xaker [14]3 years ago

3 0

Basically see where it intersectst the y axis
that is where x=0
so set x=0 and solve
3(0)^2-1/2(0)+4+1
4+1
5
the y intercept is at y=5, so yo uknow that (0,5) is on the graph

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What is the percent of incerse between 10 and 24

lisabon 2012 [21]

To work out the percent increase, we can use the following equation:

24 / 10 = 2.4
2.4 x 100 = 240%

Hope I helped!

6 0

2 years ago

Given the following triangle, what is the measure of the missing side?

Karolina [17]

It's a half of an equilateral triangle because their angles measure 30° and 60° (an equilateral triangle has 3 angles of 60°)
So x=(2h/√3)/2=h√3=27√3≈15.6

8 0

2 years ago

a 400 g of a liquid of density 1.6g/cm3 is made from mixing liquids of density 1.2g/cm3 and 1.8g/cm3 find the mass of the liquid

gogolik [260]

Answer:

133.33g

Step-by-step explanation:

Let the:

Mass of 1.2g/cm³ of liquid = x

Mass of 1.8g/cm³ of liquid = y

From our Question above, our system of equations is given as:

x + y = 400........ Equation 1

x = 400 - y

1.2 × x + 1.8 × y = 1.6 × 400

1.2x + 1.8y = 640..... Equation 2

We substitute, 400 - y for x in Equation 2

1.2(400 - y) + 1.8y = 640

480 - 1.2y + 1.8y = 640

- 1.2y + 1.8y = 640 - 480

0.6y = 160

y = 160/0.6y

y = 266.67 g

Solving for x

x = 400 - y

x = 400 - 266.67g

x = 133.33g

Therefore, the mass of the liquid of density 1.2g/cm³ is 133.33g

7 0

2 years ago

Solve the system using elimination -2x + y = 11 2x + 3y= 17

olasank [31]

Answer:

point form: (-2,7)

equation form: X = -2, Y = 7

6 0

2 years ago

Without using a calculator, determine the number of real zeros of the function

kumpel [21]

The number of real zeros of the function f(x) = x3 + 4x2 + x − 6 is 3

<h3>How to determine the number of real zeros?</h3>

The equation of the function is given as:

$f(x) = x^3 + 4x^2 + x - 6$

Expand the function

$f(x) = x^3 + 5x^2 - x^2 + 6x - 5x - 6$

Reorder the terms

$f(x) = x^3 + 5x^2 + 6x - x^2 - 5x - 6$

Factor the expression

$f(x) = x(x^2 + 5x + 6) -1(x^2 + 5x + 6)$

Factor out x -1

$f(x) = (x^2 + 5x + 6)(x -1)$

Expand

$f(x) = (x^2 + 3x + 2x + 6)(x -1)$

Factorize

$f(x) = [x(x + 3) + 2(x + 3)](x - 1)$

Factor out x + 2

$f(x) = (x + 3)(x + 2)(x- 1)$

The function has been completely factored and it has 3 linear factors

Hence, the number of real zeros of the function f(x) = x3 + 4x2 + x − 6 is 3

Read more about functions at:

brainly.com/question/7784687

#SPJ1

3 0

1 year ago