<span>Answer:
MgF2 ====⇒ Mg+2 + 2F-
Ksp = [Mg+2][F-]^2
Let S = molar solubility of MgF2
[Mg+2] = S ; [F-] = 2s
Since the [F-] is initially 0.40 M, then [F-] = 0.40 + 2S
6.4 x 10^-9 = (S) (0.40 + 2S)^2 ; one can neglect the 2S in the 0.40 + 2S expression since it is very, very small compared to the 0.40 already present.
6.4 x 10^-9 = S(0.40)^2
S = 4.0 x 10^-8
Molar solubility = 4.0 x 10^-8</span>
The ratio would be
45/100
45 to 100
45:100
Hope this helps!
First to get the equation you knew to understand one thing about perpendicular lines. The slope of the line is the opposite reciprocal of the perpendicular lines or the new slope is m = 10.
Then you use the formula
y = mx + b
you plug in your values from the point and the new slope.
(1,5) with new slope m
5= 10(1)+b
5-10=b
-5 = b
then make your new equation
y = 10x -5
that's your line that goes through point (1,5) and is perpendicular to the line given
We need to convert the mileage from mi/gal units into to km/L units using the conversion factors.
(31.0 mi/gal) x (1 km / 0.6214 mi) x (1 gal / 3.78 L) = 13.20 km/L
Next, we divide the distance by the mileage.
(142 km) / (13.20 km/L) = 10.79 L
<span>Therefore, you need 10.79 liters of gasoline.</span>
