So,
120 gal./min.
There are 4 qt. in a gal.
Multiply 120 by 4.
120(4) = 480 qt.
The pool is being drained at a rate of 480 qt./min.
Now, since there are 60 min. in an hr., multiply 480 by 60.
480(60) = 28,800 qt./hr.
The pool is being drained at a rate of 28,800 qt./hr. (quarts per hour)
Answer:
A = $8406.6
Step-by-step explanation:
Given:
Average rate 
Initial cost of painting 
Time 
We need to find the final amount of painting at the end of a 20-year.
Solution:
Using Exponential Growth rate formula as:
----------(1)
Where:
A = Final amount
a = Initial amount.
r = Rate as a decimal.
t = Time.
Now, we substitute all given values in equation 1.


Substitute
in above equation.

A = $8406.62
Therefore, value of the painting at the end of a 20-year A = $8406.6
The answer should be 3.84
The answer is B: Yes because each input has only one output