-2=-5+z/-2 Solve for z Steps on how to do this?
2 answers:
You might be interested in
Answer:
Step-by-step explanation:
Given that 33.4% of people have sleepwalked.
Sample size n =1459
Sample favourable persons = 526
Sample proportion p =
Sample proportion p is normal for large samples with mean = 0.334 and
std error =
a) P(526 or more of the 1459 adults have sleepwalked.)
b) Yes, because hardly 1.4% is the probability
c) 33.4 is very less compared to the average. Either sample should be improved representing the population or population mean should be increased accordingly.