No cuz if a number is dividable by 2 then it's even if the number is not even then it is not dividable by 2.
Make one side equal zero
minus 11 to both sides
x^2-6x-2=0
another quadratic equation
if you hahve
ax^2+bx+c=0
x=

1x^2-6x-2=0
a=1
b=-6
c=-2
x=

x=

x=

x=

x=

x=

or

aprox
x=6.31662 or -0.316625
B = no. of buses
v = no. of vans
b + v less than or equal to 8 ( there are only 8 drivers, but don't have to use them all)
51b + 8v greater than or equal to 193 (the number of seats must be at least 193 but there can be spares)
So these are the inequalities to solve. I did start doing a linear programming graph but the second inequality is horrible so I hope you don't need to actually solve them.
Step-by-step explanation:
<h2>—Math</h2>
x² – 2x + 7 = 4x – 10
x² –2x – 4x + 7 + 10= 0
x² –6x + 17 = 0
Since the others are congruent and linear so is a and b!!!!!!!!