v + m = 32 and v = 5 + 2m are the equations that are used to determine m, the number of stuffed animals Mariposa has
Number of stuffed animals Mariposa has is 9 and number of stuffed animals with Veronica is 23
<h3>
<u>Solution:</u></h3>
Let "v" be the number of stuffed animals with Veronica
Let "m" be the number of stuffed animals with Mariposa
Given that,
Together, they have 32 stuffed animals
Therefore,
v + m = 32 --------- eqn 1
Veronica has 5 more than double the number of stutted animals as her friend Mariposa
Therefore,
Number of stuffed animals with Veronica = 5 + 2(number of stuffed animals with Mariposa)
v = 5 + 2m ---------- eqn 2
Thus eqn 1 and eqn 2 can be used to determine m, the number of stuffed animals Mariposa has
Let us solve eqn 1 and eqn 2
Substitute eqn 2 in eqn 1
5 + 2m + m = 32
5 + 3m = 32
3m = 32 - 5
3m = 27
<h3>m = 9</h3>
Substitute m = 9 in eqn 2
v = 5 + 2(9)
v = 5 + 18
<h3>v = 23</h3>
Thus number of stuffed animals Mariposa has is 9 and number of stuffed animals with Veronica is 23
Step-by-step explanation:
1/3,0,9
9,3,27
1/9,3,27
Answer:
x= 5 , for c to be same on each eqn
Answer:
1. Proved down
2. proved down
3. f(10) = -20 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5
Step-by-step explanation:
Let us explain how to solve the question
∵ f(0) = -20, f(n) = f(n - 1) - 5 for n > 1
→ That means we have an arithmetic sequence with constant
difference -5 and first term -20
1. → f(1) means we need to find the second term, which equal the
term - 5
∵ f(1) means n = 1
∴ f(1) = f(1 - 1) - 5
∴ f(1) = f(0) - 5
∵ f(0) = -20
∴ f(1) = -20 - 5 → Proved
2. → f(3) means we need to find the third term, which equal the
second term - 5
∵ f(3) means n = 3
∴ f(3) = f(3 - 1) - 5
∴ f(3) = f(2) - 5
→ f(2) = f(1) - 5
∵ f(1) = -20 - 5
∴ f(2) = [-20 - 5] - 5 = -20 - 5 - 5
∴ f(3) = [-20 - 5 - 5] - 5
∴ f(3) = -20 - 5 - 5 - 5 → Proved
3. → From 1 and 2 we notice that the number of -5 is equal to n,
at n = 1 there is one (-5), when n= 3 there are three (-5)
∵ n = 10
∴ There are ten (-5)
∴ f(10) = -20 - 5(10)
∴ f(10) = -20 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5 → Proved
A ( - 4, 2)
Reflected over x = 3.
x = 3 is a vertical line, the point (-4, 2) is 7 units on the left side of the vertical line. When you reflect across the line to the right side we need to be 7 units away from the vertical line on the right side. 3 + 7 = 10
The x value would be 10. (10, 2)
LETTER D
