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Bumek [7]
2 years ago
9

What is the difference between posting and transfer in ICT please I need the answer before TMR​

Computers and Technology
1 answer:
Radda [10]2 years ago
7 0

Answer: b

Explanation: trust

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The shapes of AND, OR, and NOR gates have something in common. What is it and why do you think they share that feature?
irina1246 [14]
There're all conjunctions.

You can seperate them in sentences after a comma for a run-on sentence.
4 0
2 years ago
Determine the "answer" to the function according to the spreadsheet below: =SUM(A1:A3)/2
nataly862011 [7]
If this is the full question " <span>Which of the following formulas is equivalent to =SUM(A1:A3)? A. =A1+A3 B. =A1+A2+A3 B. =A2 D. =A3-A1"


The answer is </span>
<span>B. =A1+A2+A3 formulas is equivalent to =SUM(A1:A3)</span>
4 0
3 years ago
There are n poor college students who are renting two houses. For every pair of students pi and pj , the function d(pi , pj ) ou
Nuetrik [128]

Answer:

Here the given problem is modeled as a Graph problem.

Explanation:

Input:-  n, k and the function d(pi,pj) which outputs an integer between 1 and n2

Algorithm:-We model each student as a node. So, there would be n nodes. We make a foothold between two nodes u and v (where u and v denote the scholars pu and pv respectively) iff d(pu,pv) > k. Now, Let's call the graph G(V, E) where V is that the vertex set of the graph ( total vertices = n which is that the number of students), and E is that the edge set of the graph ( where two nodes have edges between them if and only the drama between them is bigger than k).

We now need to partition the nodes of the graph into two sets S1 and S2 such each node belongs to precisely one set and there's no edge between the nodes within the same set (if there's a foothold between any two nodes within the same set then meaning that the drama between them exceeds k which isn't allowed). S1 and S2 correspond to the partition of scholars into two buses.

The above formulation is akin to finding out if the graph G(V,E) is a bipartite graph. If the Graph G(V, E) is bipartite then we have a partition of the students into sets such that the total drama <= k else such a partition doesn't exist.

Now, finding whether a graph is bipartite or not is often found using BFS (Breadth First algorithm) in O(V+E) time. Since V = n and E = O(n2) , the worst-case time complexity of the BFS algorithm is O(n2). The pseudo-code is given as

PseudoCode:

// Input = n,k and a function d(pi,pj)

// Edges of a graph are represented as an adjacency list

1. Make V as a vertex set of n nodes.

2. for each vertex  u ∈ V

\rightarrow  for each vertex v ∈ V

\rightarrow\rightarrowif( d(pu, pj) > k )

\rightarrow\rightarrow\rightarrow add vertex u to Adj[v]   // Adj[v] represents adjacency list of v

\rightarrow\rightarrow\rightarrow add vertex v to Adj[u] // Adj[u] represents adjacency list of u

3.  bool visited[n] // visited[i] = true if the vertex i has been visited during BFS else false

4. for each vertex u ∈ V

\rightarrowvisited[u] = false

5. color[n] // color[i] is binary number used for 2-coloring the graph  

6. for each vertex u ∈ V  

\rightarrow if ( visited[u] == false)

\rightarrow\rightarrow color[u] = 0;

\rightarrow\rightarrow isbipartite = BFS(G,u,color,visited)  // if the vertices reachable from u form a bipartite graph, it returns true

\rightarrow\rightarrow if (isbipartite == false)

\rightarrow\rightarrow\rightarrow print " No solution exists "

\rightarrow\rightarrow\rightarrow exit(0)

7.  for each vertex u ∈V

\rightarrow if (color[u] == 0 )

\rightarrow\rightarrow print " Student u is assigned Bus 1"

\rightarrowelse

\rightarrow\rightarrow print " Student v is assigned Bus 2"

BFS(G,s,color,visited)  

1. color[s] = 0

2. visited[s] = true

3. Q = Ф // Q is a priority Queue

4. Q.push(s)

5. while Q != Ф {

\rightarrow u = Q.pop()

\rightarrow for each vertex v ∈ Adj[u]

\rightarrow\rightarrow if (visited[v] == false)

\rightarrow\rightarrow\rightarrow color[v] = (color[u] + 1) % 2

\rightarrow\rightarrow\rightarrow visited[v] = true

\rightarrow\rightarrow\rightarrow Q.push(v)

\rightarrow\rightarrow else

\rightarrow\rightarrow\rightarrow if (color[u] == color[v])

\rightarrow\rightarrow\rightarrow\rightarrow return false // vertex u and v had been assigned the same color so the graph is not bipartite

}

6. return true

3 0
3 years ago
How do you open the Font dialog?​
Simora [160]

Explanation:

Click the Home tab.

In the Fonts group, click the dialog box launcher button.

The button is found in the lower-right corner of the Font group.

The Font dialog box contains all the commands for formatting text, including quite a few that didn’t find their way into the Font group on the Ribbon. As with all text formatting, the commands you choose in the Font dialog box affect any new text you type or any selected text in your document.

When you’ve finished setting up your font stuff, click the OK button. Or click Cancel if you’re just visiting.

Use the Ctrl+D keyboard shortcut to quickly summon the Font dialog box.

hope my answer helps

pls mark this as brainlist

be sure to follow me and I will follow you back

stay safe

good day

6 0
2 years ago
operating systems for mobile devices can support full-scale software programs like Microsoft Word or Excel
goldfiish [28.3K]
Mobile devices are unable to run full scale software programs like MS Word or Excel. They can run apps however with smaller capabilities as they require less hardware and specifications than the full version
The answer is false
7 0
3 years ago
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