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3 years ago

Determine the amounts of 20% and 50% salt solutions that should be mixed to obtain 300 gallons of 41% salt solution.

1 answer:

3 0

Assume that solution with 20% and 50% salt is x and y gallons respectively.

Therefore,

x+y = 300 => y=300-x

Additionally
20x+50y = 300*41 = 12300

Substituting for y

20x+50(300-x) = 12300 => 20x+15000-50x = 123000 => -30x = -2700

x= 90 gallons
y= 300-x = 300 - 90 =210 gallons

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2 years ago

Using this formula l=A 1/2 what is the length of one side of a square with an area of 1,936 square kilometers? (A is the area of

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c.)44 kilometers

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Solution given:

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length =L

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Area =A

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we have

Area [A]=1936 square kilometers

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Area of square :length *length

A=l*l

A=l²

Substituting value of A

1936=l²

doing square root on both side

$\sqrt{1936}=\sqrt{l²}$

we get

l= $\sqrt{2*2*2*2*11*11}$

l=2*2*11

l=44 kilometers

the length of one side of a square is 44 kilometers.

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