<h3>
Answer: (x² + 1)(x + 1)</h3>
Work Shown:
x³ + x² + x + 1
(x³ + x²) + (x + 1)
x²(x+1) + 1(x + 1)
(x² + 1)(x + 1)
The basic outline is to pair up the terms into two groups. We factor each group separately, and then factor out the overall GCF (x+1). You can use the FOIL rule to verify the answer.
Answer:
A Square, Rectangle, and a Rhombus
Step-by-step explanation:
I think that is all of them.
0 = -16t²+64t+80
Finding the roots of the equation:
-16(t² - 4t - 5) = 0
-16(t-5)(t+1) = 0
t = 5, t = -1. Time cannot be negative, so after 5 seconds it will hit the ground.
Answer:
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